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otez555 [7]
2 years ago
11

Please help c=x+b solve for x

Mathematics
1 answer:
fredd [130]2 years ago
5 0

Answer:

x = c - b

Step-by-step explanation:

c = x + b

Subtract b on both sides,

c - b = x + b - b

c - b = x

x = c - b

Hence, solved.

You might be interested in
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

4 0
3 years ago
If a ∝ b and a = 18 when b = 3, then find a when b = 5.
Elden [556K]

"a ∝ b" means "a is proportional to b", which in turn means there is some constant k such that

a = kb

We're given that a = 18 and b = 3, so that

18 = 3k   ⇒   k = 6

Then when b = 5, we would have

a = 6 × 5 = 30

4 0
2 years ago
Please anyone help me with this please!!?​
Nataly [62]

Answer:

I think it's (-3, 1)

Hope this helps! :)

7 0
3 years ago
Use the discriminant of the following quadratic equation to state the number and type of solutions. 3x^(2)+4x-5=3x+2
krek1111 [17]
3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions
4 0
3 years ago
Find the recursive formula for 15,12,9,6,
makkiz [27]
An=an-1-3

I hope this helps.
4 0
3 years ago
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