Solve for x.

Tyrone makes a scale drawing of his backyard. The scale from the backyard to the drawing is 2 ft to 1 in. The width of the patio

Sphinxa [80]

Answer:

The width of Tyrone's actual patio is 16 feet

Step-by-step explanation:

$\frac{2ft}{1in}$ = $\frac{x}{8}$ If we look at what we know, we see that the scale tells us that 1 inch is proportional to 2 ft. What do we need to multiple 1 inch by to get 8 inches? 8. So, we multiply 2 feet by 8 to get the actual size of the patio which is 16 feet.

6 0

1 year ago

You want to have $25,000 for a down payment on a house 6 years from now. if you can earn 6.5 percent, compounded annually, on yo

STatiana [176]

Use compound interest formula:
Future value, F
25000=P(1+i)^n
where
P=present value to be found
i=annual interest rate = 0.065
n=number of years = 6
so
25000=P(1.065)^6
=>
P=(25000/1.065^6)=$17133.353

6 0

3 years ago

What is the first step in solving quadratic equations by finding square roots? a. give the positive and negative answer C. b. is

tangare [24]

The first step in solving quadratic equations by finding square roots is; C:square root both sides to isolate x

<h3>How to solve quadratic equations?</h3>

To answer this question, we will take an example of a quadratic equation that we need to find the square root as;

x² = 36

Now, to get the roots which are the values of x, we will first have to take the square root of both sides to Isolate x. Thus;

√x² = √36

x = ±6

Read more about quadratic equations at; brainly.com/question/1214333

#SPJ1

6 0

2 years ago

What is the slope of the line shown?

sashaice [31]

The slope would be -1/3

3 0

3 years ago

Read 2 more answers

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago