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Gekata [30.6K]
2 years ago
8

Find vertex of f(x)=(x+3)(x-5)

Mathematics
2 answers:
Alja [10]2 years ago
6 0
Answer: (1,-16) hopes this helps!
astra-53 [7]2 years ago
4 0

The x coordinate of the vertex will be the average of the two zeros, here -3 and 5, so x=(-3+5)/2 = 1, f(1)=(1+3)(1-5) = -16.

Answer: (1, -16)

Let's do it some other ways.  How about completing the square to turn f in to vertex form?

f(x) = (x+3)(x-5) = x² - 2x - 15 = (x² - 2x + 1) - 1 - 15 = (x-1)² - 16

and now we can read off (1, -16) as the vertex.

The other method is the vertex is x= - b/2a =  - (-2)/2(1) = 1.

Three methods, same answer. Good.

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Q # # 12 find the volume of the cylinder to the nearest cubic foot Use a calculator
Ronch [10]
The diagram in the question is a cylinder.
;The volume of a cylinder is given by;

Volume = πr²h
;Where π=3.14
             r⇒radius of the base of the cylinder and
             h ⇒ height of the cylinder.

∴Volume = 3.14×5²×3
               =235.5 ft³

To the nearest cubic = 236 ft³

4 0
3 years ago
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10x²-17x+3 (factor this polynomial in a 3x3 table form) picture please
Ymorist [56]
(2x-3)(5x-1). I Think that is the answer.
3 0
3 years ago
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Find the indefinite integral. (Use C for the constant of integration.)
mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

u=(x^3-x^2+x)

Then

du = (3x^2-2x+1) dx

which allows us to do convert the original integral into a much simpler one of easy solution:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx  = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C

Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

7 0
3 years ago
Will give brainlisted whoever is correct first. please hurry.
kipiarov [429]

Answer:

32.33 <= m

Step-by-step explanation:

Since we are dealing with below sea level our initial starting point and max level will both be negative values, while our descending rate will also be negative because we are going down. Using the values provided we can create the following inequality...

-400 <= -12m - 12

Now we can solve the inequality to find the max number of minutes that the submarine can descend.

-400 <= -12m - 12   ... add 12 on both sides

-388 <= -12m   ... divide both sides by -12

32.33 <= m

3 0
2 years ago
what is the distance between (0, -2) and (9, 10) ? please show your work so i can understand thank you
Setler [38]

Given:

The two points are (0, -2) and (9, 10).

To find:

The distance between the given points.

Solution:

Distance between the two points is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the above distance formula, the distance between given points is

d=\sqrt{(9-0)^2+(10-(-2))^2}

d=\sqrt{(9)^2+(10+2)^2}

d=\sqrt{81+(12)^2}

On further simplification, we get

d=\sqrt{81+144}

d=\sqrt{225}

d=15

Therefore, the distance between the given points (0,-2) and (9,10) is 15 units.

4 0
2 years ago
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