Find vertex of f(x)=(x+3)(x-5)

Mathematics

2 answers:

Alja [10]3 years ago

6 0

Answer: (1,-16) hopes this helps!

astra-53 [7]3 years ago

4 0

The x coordinate of the vertex will be the average of the two zeros, here -3 and 5, so x=(-3+5)/2 = 1, f(1)=(1+3)(1-5) = -16.

Answer: (1, -16)

Let's do it some other ways. How about completing the square to turn f in to vertex form?

f(x) = (x+3)(x-5) = x² - 2x - 15 = (x² - 2x + 1) - 1 - 15 = (x-1)² - 16

and now we can read off (1, -16) as the vertex.

The other method is the vertex is x= - b/2a = - (-2)/2(1) = 1.

Three methods, same answer. Good.

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$\huge\textbf{Hey there!}$

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