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NeTakaya
3 years ago
14

Amy purchased a brand-new mountain bike, which she's riding through

Mathematics
1 answer:
Neko [114]3 years ago
5 0

Answer:

The Acceleration of bike after 3 minutes of ride is  14 meter² per minutes

Step-by-step explanation:

Given as :

The displacement of bike is the function of time

i.e s(t) = t³ - 2 t² + 3  meters

The Time of bike acceleration = t = 3 minutes

Let The Acceleration of bike = a meter² per minutes

Now, According to question

∵ <u>Acceleration is define as the rate of change of velocity</u>

i.e acceleration = \dfrac{\textrm velocity}{\textrm time}

or, a =  \dfrac{\textrm v}{\textrm t}

And

<u>Velocity is define as rate of change of displacement</u>

i.e velocity =  \dfrac{\textrm displacement}{\textrm time}

Or, v =  \dfrac{\textrm s}{\textrm t}

Since here displacement is function of time

So , v = \frac{\partial s(t)}{\partial t}

Or, v =   \frac{\partial (t³ - 2 t² + 3)}{\partial t}

Or, v = 3 t² - 4 t + 3

So, velocity is the function of time = v = 3 t² - 4 t + 3   meter per minutes

Now, Again

Acceleration = a = \frac{\partial v}{\partial t}

Or, a = \frac{\partial (3 t² - 4 t + 3)}{\partial t}

Or, a = 6 t - 4

∴  Acceleration is the function of time = a = 6 t - 4

Now, Acceleration of bike after 3 minutes

So, at t = 3 min

i.e a = 6 t - 4

Or, a = 6 × 3 - 4

Or, a = 18 - 4

∴  a = 14 meter² per minutes

Hence, The Acceleration of bike after 3 minutes of ride is  14 meter² per minutes . Answer

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In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE║ AB. Find the measures of the angles of ΔABC, if m∠ADE: m∠ADB = 2
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Answer:   ∠A=48°,∠B=48°,∠C=84°.


Step by-step explanation:

Given:  AD and BE are the angle bisectors  of ∠A and ∠B

i.e ∠6=∠7    ( ∵ Angles formed after  AD bisected ∠A)

∠4=∠5       ( ∵ Angles formed after  BE bisected ∠B)

Also,  DE║AB

⇒ ∠2=∠7   (∵ Alternate interior angles)

   ∠3=∠6   (∵ Alternate interior angles)

And ∠ADE : ∠ADB =∠2:∠3= 2:9 =2x : 9x     ..(1)

To Find:  ∠A,∠B,∠C.

Solution:  ∠2=∠7 (∵ Given)    ...(2)

∠2=∠4  (∵ angles on the same segment)    ...(3)

∠4=∠5 =∠B/2 (∵ Given)    ...(4)

∴ In Δ ABD

∠3+∠4+∠5+∠7 = 180 (∵ Sum of interior angles of a triangle)

From equation 2,3,4,5, Put values

9x+2x+2x+2x =180°

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Putting values in equation (4) ⇒ ∠ B =2*(2*12) = 48°

Also, <u>∠B=∠A=48°</u>

Now,in Δ ABC

∠C+∠B+∠A= 180°

⇒48°+48°+∠C= 180°

<u><em>⇒∠C=84°</em></u>

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