<span>f(x) = 2(0.75)^x
at x = 3
>> </span>f(3) = 2(0.75)^3
>> f(3) = <u>0.84375</u>
Answer:440.925
Step-by-step explanation:
Answer:
-2 < x < 2
Step-by-step explanation:
Divide each term by U and simplify. X=y/U and W=2/U. Next, solve the equation for y. Simplify the left side then cancel the common factor of U. 1/1*y/1=y
W=2/U. Multiply 1/1*y/1=y/1 so, y/1=y and W=2/U. Next, divide y/y to get 1 now y=y, still W=2/U. Now, move all terms containing y to the left side. Since, Y contains the variable to solve for, move it to the left side of the equation by subtracting y from both sides. Now, y-y=0 still W=2/U. Next, subtract y from y to get zero and still W=2/U. Subtract y from y to get zero or 0=0 and W=2/U is your expression since 0=0.
Next: UW=m and WX=y+14 write expression for UX
First, divide each term by W and simplify. U=m/W, WX=y+14. Next, solve the equation for Y. Move y from the right side of the equation to the left side. Still, U=m/W and y=-14+WX. We must reorder -14 and WX. U=m/w and y=WX-14.
Replace the variable U with m/W in the expression to (m/W)X. Next, simplify (m/W)X. Now, write X and a fraction with denominator 1. Looks like this
fractions are side by side m/W X/1 . Multiply, m/W and X/1 to get mX/W.
mX/W is your final expression for UW=m and WX=y+14 expression for UX.
Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,
Here, ,Perpendicular AB = 4000
Solving for BC, we get,
(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft