S=cost per student ticket
a=cost per adult ticket
value=(students vlue)+(adults value)
student value=(cost per student) times number of students
adult value=(cost per adult) times number of adults
you sell 8 adult and 6 students and that is a value of 126
8a+6s=126
friend sell12 adult and 13 student and get 209
12a+13s=209
so we have
8a+6s=126 and
12a+13s=209
it might help to simplify the first equaiton by dividing by 2
4a+3s=63
we have
4a+3s=63
12a+13s=209
multiply first equaton by -3
-12a-9s=-189
add to secont equaiton
12a+13s=209
<u>-12a-9s=-189 +
</u>0a+4s=20<u> </u>
4s=20
divide 4
s=5
each student ticket costs $5.00
You should use a T distribution to find the critical T value based on the level of confidence. The confidence level is often given to you directly. If not, then look for the significance level alpha and compute C = 1-alpha to get the confidence level. For instance, alpha = 0.05 means C = 1-0.05 = 0.95 = 95% confidence
Use either a table or a calculator to find the critical T value. When you find the critical value, assign it to the variable t.
Next, you'll compute the differences of each pair of values. Form a new column to keep everything organized. Sum everything in this new column to get the sum of the differences, which then you'll divide that by the sample size n to get the mean of the differences. Call this dbar (combination of d and xbar)
After that, you'll need the standard deviation of the differences. I recommend using a calculator to quickly find this. A spreadsheet program is also handy as well. Let sd be the standard deviation of the differences
The confidence interval is in the form (L, U)
L = lower bound
L = dbar - t*sd/sqrt(n)
U = upper bound
U = dbar + t*sd/sqrt(n)
Answer:
172
Step-by-step explanation:
864 / 5 = 172.8
And so there cant' be a half of a bead, so thre is 172.
If you times 2 negatives together you will get a positive
Answer:
(x + 3)
Step-by-step explanation:
Using the zero product property
x-a = 0 x-b = 0 where a and b are the zeros
(x-a)(x-b) =0
(x- -3)(x -8) =0
(x+3) (x-8) =0
