Answer:
Step-by-step explanation:
Note that there are two scale models with each of ratio of 1/2 and 1/16 respectively.
For the first model, the dimension will be as follows:
Length/2 by width/2
94/2 by 50/2 = 47 feet by 25 feet.
For the second model, the dimension will be as follows:
Length/16 by width/16
The dimensions of the second model is 94/16 by 50/16 = 5.875 feet by 3.125 feet.
Since we are to solve for the area of the smallest scale model which is
5.875 feet by 3.125 feet.
Hence, area (A) = L× W
=5.875 × 3.125 feet.
= 18.359ft^2
Answer:
12.686cm
Step-by-step explanation:
By using pythagoras, we can find CB.
We know that 
Therefore, 
(it has to be positive since it is distance)
now we look at triangle BCD and use SOH CAH TOA.
Answer:
To find this out you would take the amount of yellow bricks minus the amount of bricks in total
so
14 blocks - 6 yellow blocks = 8 blocks
from this information we can conclude that jay has 8 green blocks
Step-by-step explanation:
Answer: (15/2, 33/2) or (7.5, 16.5)
depending on if you want fractions or decimals
explanation:
equation for midpoint... (avg x, avg y)
x-coordinate: (6+9)/2 = 15/2 = 7.5
y-coordinate: (17+16)/2 = 33/2 = 16.5
Answer:
The Gold team has 8 swimmers and the silver team also has 8 swimmers.
Step-by-step explanation:
Let T be the total number of swimmers on the Gold team. Since, the Gold team has a 2:3 ratio of 11 year olds to 12 year olds, the number of 11 year old is T' = 2/(2 + 3) × T = 2T/5 and the number of 12 year olds is T" = 3/(2 + 3) × T = 3T/5.
The silver team has a 3:8 ratio of 11 year olds to the total swimmers. Let T₁ be the number of 11 year old swimmers in the silver team. So, from the ratio 3:8, the number of 11 year old swimmers in the silver team is 3 and the total number of swimmers in the silver team is 8.
Since the number of 11 year old swimmers in both teams are the same, then
2T/5 = 3
T = 3 × 5 ÷ 2
T = 15/2
T = 7.5
T≅ 8
So, the Gold team also has 8 swimmers.
So, the Gold team has 8 swimmers and the silver team also has 8 swimmers.
