All categories

1 year ago

Kyle is buying a new car. The car can be driven 24.3 miles with one gallon of gas. The

Mathematics

1 answer:

lana [24]1 year ago

6 0

Answer:

371.79miles

Step-by-step explanation:

24.3 miles = 1 gallon of gas

★miles = 15.3 gallon of gas

24.3 × 15.3 =371.79miles

You might be interested in

A number cube has sides that are labeled 1 to 6. Jamal rolls the number cube. What is the probability that he will roll a 22?

Tems11 [23]

-- The probability of rolling a 22 is zero. That result is impossible, because the sides are labeled with single digits 1 through 6 . Since 22 is not printed anywhere on the cube, it can never come up.

-- The probability of rolling a 2 , however, is 1/6 . (B)

The -probability of rolling something you want is always

(the number of different possible results that you like)

divided by

(the total number of different possible results)

4 0

2 years ago

What is the domain of this exponential function?

Pavlova-9 [17]

Answer:

Domain = x E R

Step-by-step explanation:

Since an exponential function has no restriction on the "x" value, its domain can range from anywhere on the plane of "x."

3 0

2 years ago

Share 1200kg in the ratio 3:37

bearhunter [10]

Answer:

3+37=40

3/40×1200=90kg

37÷40×1200=1110kg

Step-by-step explanation:

''.''

5 0

2 years ago

Read 2 more answers

A pair of parallel lines intersected by a transversal and forms same side interior angles that are in a 5:1 ratio. what are the

kifflom [539]

Answer:

1st side: 150

2nd side: 30

3 0

2 years ago

Which equation has the solutions x = -3 ± √3i/2 ?

Maurinko [17]

Answer:Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

Note: None of options matches with given question.

instead of "-3" , there should be "- $\frac{3}{2}$ ".

Step-by-step explanation:

Note: None of options matches with given question.

instead of "-3" , there should be " $\frac{3}{2}$ ".

Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + x( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i)+ x( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + $\frac{3}{2}$ x + $\frac{\sqrt{3}}{2}$ ix + $\frac{3}{2}$ x - $\frac{\sqrt{3}}{2}$ ix + (3- $\frac{\sqrt{3}}{2}$ i)(3+ $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{3}{4}$ ) $i^{2}$ ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ + ( $\frac{3}{4}$ ) ] =0

∴ [ $x^{2}$ + 3x + $\frac{12}{4}$ ] =0

∴ [ $x^{2}$ + 3x + 3 ] =0

Thus, Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

6 0

3 years ago