Answer:
The line crosses the y-axis at -2
Step-by-step explanation:
y = mx + b 'm is the slope and b is the y-intersect (the place where the graph comes across the y-axis.
y = mx + b; y = mx + b; b = -2.
When reflecting across the Y axis, the Y values remain the same.
Now if you were reflecting across Y = 0, the x values would just be inverse ( opposite signs).
So this triangle if reflected across Y = 0 the new vertices would be (4,4) (2,3) and (5,2)
Now since the reflection line is y = -1, which is a one unit shift to the left of y = 0, subtract 1 unit from each X value.
The locations are now: A'(3,4), B'(1,3) and C'(4,2)
Answer:
A
Step-by-step explanation:
I don't think you have the right equation down, so this more of an educated guess than an actual direct answer
Answer:
Option D.
Step-by-step explanation:
The given expression is

It is a polynomial.
(x-c) is a linear factor of polynomial p(x) if p(c)=0.
Substitute x=-1 in the given expression.

It means (x+1) is not a linear factor of given expression.
Substitute x=-2 in the given expression.

It means (x+2) is not a linear factor of given expression.
Substitute x=-4 in the given expression.

It means (x+4) is not a linear factor of given expression.
None of the given options are a linear factor of given expression.
Therefore, the correct option is D.