Does anyone know 4 copies over 1/5?

which of these can be rewritten as an exact answer without the square root symbol? √4 √125 √0.6 √12.35 Thank you :)

Goshia [24]

Answer:

$\sqrt{4}$

Step-by-step explanation:

Because

→ $\sqrt{4}$ is equal to 2

→ $\sqrt{125}$ is equal to $5\sqrt{5}$ or 11.18033989

→ $\sqrt{0.6}$ is equal to $\frac{\sqrt{15} }{5}$ or 0.7745966692

→ $\sqrt{12.35}$ is equal to 3.514256678

6 0

4 years ago

Read 2 more answers

Someone please help Other option is 120

MariettaO [177]

130 degrees!That should be your answer. :) Hope i helped

8 0

4 years ago

Need Help ASAP

irga5000 [103]

Given that mean of quiz scores = 6.4 and standard deviation = 0.7

And we need to use Chebyshev's theorem to find the range in which 88.9% of data will reside.

Chebyshev's theorem states that "Specifically, no more than $\frac{1}{k^{2} }$ of the distribution's values can be more than k standard deviations away from the mean".

That is $1-\frac{1}{k^{2} } = 0.889$

$\frac{1}{k^{2} } = 1-0.889 = 0.111$

$k^{2} = \frac{1}{0.111}$

k = 3

So, we want the range of values within 3 standard deviations of mean.

Hence range is [mean -3*standard deviation, mean +3*standard deviation]

= [6.4 - 3*0.7 , 6.4+3*0.7]

= [6.4 - 2.1 , 6.4+2.1] = [4.3,8.5]

3 0

4 years ago

PLEASE help me solve this problem. I really need help.

mote1985 [20]

When:
a = b = 0 we have point (0,0).
a = 0 and b ≠ 0 vertical line segment from (0, -b) to (0, b)
a ≠ 0 and b = 0 horizontal line segment from (-a, 0) to (a, 0)
a ≠ 0 and b ≠ 0 a ≠ b ellipse
a ≠ 0 and b ≠ 0 a = b circle

3 0

3 years ago

the total attendance at a concert in a theater hall was 1500, of this total 400 were children,850 were women , and the remaining

AleksandrR [38]

Answer:

Below!

Step-by step explanation:

We know that:

400 + 850 + m = 1500

Solution of Question A:

Percent of children: Total children/Total attendance

=> 400/1500
=> 4/15
=> 0.27 (Rounded to nearest hundredth)
=> 0.27 x 100
=> 27%

Hence, the percent of children is about 27%.

Solution of Question B:

Percent of women: Total women/Total attendance

=> 850/1500
=> 85/150
=> 17/30
=> 17/30 x 100
=> 17/3 x 10
=> 170/3
=> 56.67%

Hence, the percent of women is 56.67%.

Solution of Question C:

400 + 850 + m = 1500
=> 1250 + m = 1500
=> m = 1500 - 1250
=> m = 250

Percent of men: Total men/Total attendance

=> 250/1500
=> 1/6
=> 0.17 (Rounded to nearest hundredth)
=> 0.17 x 100
=> 17%

Hence, the percent of men is about 17%

Hoped this helped.

$BrainiacUser1357$

3 0

2 years ago