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KIM [24]
2 years ago
13

Does anyone know 4 copies over 1/5?

Mathematics
1 answer:
morpeh [17]2 years ago
3 0
The answer is 4/5 your welcome
You might be interested in
which of these can be rewritten as an exact answer without the square root symbol? √4 √125 √0.6 √12.35 Thank you :)
Goshia [24]

Answer:

\sqrt{4}

Step-by-step explanation:

Because

→ \sqrt{4}  is equal to 2

→ \sqrt{125}  is equal to  5\sqrt{5} or 11.18033989

→ \sqrt{0.6}  is equal to  \frac{\sqrt{15} }{5}  or  0.7745966692

→ \sqrt{12.35}  is equal to 3.514256678

6 0
4 years ago
Read 2 more answers
Someone please help <br><br> Other option is 120
MariettaO [177]
130 degrees!That should be your answer. :) Hope i helped
8 0
4 years ago
Need Help ASAP
irga5000 [103]

Given that mean of quiz scores = 6.4 and standard deviation = 0.7

And we need to use Chebyshev's theorem to find the range in which 88.9% of data will reside.

Chebyshev's theorem states that "Specifically, no more than \frac{1}{k^{2} } of the distribution's values can be more than k standard deviations away from the mean".

That is 1-\frac{1}{k^{2} }  = 0.889

\frac{1}{k^{2} }  = 1-0.889 = 0.111

k^{2}  = \frac{1}{0.111}

k = 3

So, we want the range of values within 3 standard deviations of mean.

Hence range is [mean -3*standard deviation, mean +3*standard deviation]

                      = [6.4 - 3*0.7 , 6.4+3*0.7]

                      = [6.4 - 2.1 , 6.4+2.1] = [4.3,8.5]

3 0
4 years ago
PLEASE help me solve this problem. I really need help.
mote1985 [20]
When:
a = b = 0 we have point (0,0).
a = 0 and b ≠ 0 vertical line segment from (0, -b) to (0, b)
a ≠ 0 and b = 0 horizontal line segment from (-a, 0) to (a, 0)
a ≠ 0 and b ≠ 0 a ≠ b ellipse
a ≠ 0 and b ≠ 0 a = b circle
3 0
3 years ago
the total attendance at a concert in a theater hall was 1500, of this total 400 were children,850 were women , and the remaining
AleksandrR [38]

<u>Answer:</u>

Below!

<u>Step-by step explanation:</u>

<u>We know that:</u>

  • 400 + 850 + m = 1500

<u>Solution of Question A:</u>

<u>Percent of children: Total children/Total attendance</u>

  • => 400/1500
  • => 4/15
  • => 0.27 (Rounded to nearest hundredth)
  • => 0.27 x 100
  • => 27%

<u>Hence, the percent of children is about 27%.</u>

<u>Solution of Question B:</u>

<u>Percent of women: Total women/Total attendance</u>

  • => 850/1500
  • => 85/150
  • => 17/30
  • => 17/30 x 100
  • => 17/3 x 10
  • => 170/3
  • => 56.67%

<u>Hence, the percent of women is 56.67%.</u>

<u>Solution of Question C:</u>

  • 400 + 850 + m = 1500
  • => 1250 + m = 1500
  • => m = 1500 - 1250
  • => m = 250

<u>Percent of men: Total men/Total attendance</u>

  • => 250/1500
  • => 1/6
  • => 0.17 (Rounded to nearest hundredth)
  • => 0.17 x 100
  • => 17%

<u>Hence, the percent of men is about 17%</u>

Hoped this helped.

BrainiacUser1357

3 0
2 years ago
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