4.428571
I know because I googled it
That would be -0.041
-0.125/3 = -0.041666666
9 / 5/8 =
9/1 / 5/8 =
9/1 * 8/5 = 72/5 = 14 2/5
(It might also have helped immensely if you had been listening
when this was being explained in class.)
The first pipe fills 1/20 of the tank each minute.
The second pipe fills 1/30 of the tank each minute.
Operating together, the two pipes fill ( 1/20 + 1/30 ) of the tank each minute.
In order to add these fractions (or any fractions), you need a common denominator.
For these particular ones, ' 60 ' is a good choice.
( 1/20 + 1/30 ) = ( 3/60 + 2/60) = 5/60 = 1/12
The rate of work is 1/12 tankful per minute .
The most sensible choice for the time is 12 minutes.
R x T = W
( 1/12 tankful per minute ) x ( 12 minutes ) = 1 full tank
Answer:
f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192
Step-by-step explanation:
We have the function f(x) = x^2 − x − 12 and g(x) = x^2 − 16 and we need to find the multiplication of both functions.
f(x) × g(x) = ( x^2 − x − 12)(x^2 − 16) = x^4 - 16x^2 -x^3 + 16x -12x^2 + 192
Simplifying:
f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192
