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ANEK [815]
4 years ago
5

What is the following quotient? 5/ sqrt 11 - sqrt 3

Mathematics
2 answers:
ololo11 [35]4 years ago
6 0

Answer:

The correct option is b) \frac{5\sqrt{11}+5\sqrt{3}}{8}

Step-by-step explanation:

We need to find the quotient of \frac{5}{\sqrt{11}-\sqrt{3}},

Rationalizing the above,

By multiply and divide by conjugate of its denominator,

\frac{5}{\sqrt{11}-\sqrt{3}} \times \frac{\sqrt{11}+\sqrt{3}}{\sqrt{11}+\sqrt{3}}

\frac{5(\sqrt{11}+\sqrt{3})}{(\sqrt{11}-\sqrt{3})(\sqrt{11}+\sqrt{3})}

Since, (a+b)(a-b)=a^{2}-b^{2}

\frac{5\sqrt{11}+5\sqrt{3}}{(11-3)}

simplify,

\frac{5\sqrt{11}+5\sqrt{3}}{8}

Therefore, the correct option is b) \frac{5\sqrt{11}+5\sqrt{3}}{8}

nasty-shy [4]4 years ago
3 0

 

\displaystyle\\\frac{5}{\sqrt{11}-\sqrt{3}}=?\\\\\\\text{We rationalize the denominator.}\\\\\frac{5}{\sqrt{11}-\sqrt{3}}=\frac{5(\sqrt{11}+\sqrt{3})}{(\sqrt{11}-\sqrt{3})(\sqrt{11}+\sqrt{3})}=\frac{5(\sqrt{11}+\sqrt{3})}{(11-3)}=\boxed{\bf\frac{5\sqrt{11}+5\sqrt{3})}{8}}

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