a game is played with tokens according to the following rule and each round the player with the most tokens gives one token to e

Question

2 years ago

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a game is played with tokens according to the following rule and each round the player with the most tokens gives one token to e

ach of the other players and also places one token in the discard pile the game and win some player runs out of tokens Evelyn Amelia and Ava start with 17 16 and 15 tokens respectively how many rounds will there be in the game

Mathematics

1 answer:

gulaghasi [49] · Answer 1 · 2022-12-15T03:20:19+03:00

Answer:

47 rounds and Eve wins.

Step-by-step explanation:

If read right, the highest player, (player with the most tokens) has to lose 3 tokens each round, so starting off with Evelyn, 17 - 3 = 14, and the other two each have +1 added to them, so, E=14, A=17 V=16, now subtract three from A (Amelia) and don't forget that one token is always being discarded each round. So the toal number of tokens at the start was 48, (17 + 16 + 15) so right now the total tokens should be 47, which it is. now starting the second round, A gives up 3 tokens so, 17 -3, again equals 14 and each of the two other players get one token, so E=15, A=14 V=17. Now you know the general trend, so we can figure this out seeing that after each round the number of tokens decrease by one, so there will be a round till all tokens are out except one, so there will be 47 rounds and since E started with the highest number they will win.