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Degger [83]
3 years ago
14

What is the typical first shot that everyone takes? In photography

Computers and Technology
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

the sky or of nature in general

Explanation:

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True or Flase<br><br> In C++, the body of a for loop may never run even once.
stiks02 [169]

Answer: True

Explanation: For loop is used in the C++ programming is defined as the statement that defines about the flow control .This loop works under some condition that is considered.

For loop is evaluated to execute for one time if the statement condition is true but there are also chances of no execution at all because of the incorrect condition. So, for loop might not run even once in that condition.Thus , the statement given is true.

3 0
3 years ago
A large gambling company needs to be able to accept high volumes of customer wagers within short timeframes for high-profile spo
Dima020 [189]

Answer: A. a mobile app that only accepts wagers based on the user's location

Explanation:

Elastic cloud simply refers to the cloud computing offering which due to the need for change helps in the provision of variable service levels.

Based on the information given in the question, an effective elastic Cloud solution that can meet this client’s needs is a mobile app that only accepts wagers based on the user's location.

Since there are strict laws that prohibit gambling activities outside the licensed zones, the user location is vital in the mobile app.

5 0
3 years ago
The instructions for the OS provided by application software are known as _____.
Galina-37 [17]

Answer:

Pp

Explanation:

I like pp

7 0
3 years ago
1. For the following program to be executed over the single accumulator
AlexFokin [52]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

#include <iostream> // it is preprocessor director that manipulate the input output in the program

using namespace std;// it is used to format input and output

int main() { // main function is started

int x = 5; // variable x is declared and initialized with value 5.

int y = 6; //variable y is declared and initialized with value 6.

int z = 34;  //variable z is declared and initialized with value 34.

int total = (x+(x + y)*z+y); // variable total is declared and initialized with value of x,y,and z. and calculation performed on these value such as (5+(5+6)*34+6) that is equal to 385.

cout << total; // print the value of total variable that is 385

return 0;

}​

6 0
3 years ago
Below is a list of 32-bit memory address references, given as word addresses.
Maru [420]

For a direct mapped cache the general rule is: first figure out the bits of the offset (the right-most bits of the address), then figure out the bits of the index (the next-to right-most address bits), and then the tag is everything left over (on the left side).

One way to think of a direct mapped cache is as a table with rows and columns. The index tells you what row to look at, then you compare the tag for that row, and if it matches, the offsettells you which column to use. (Note that the order you use the parts: index/tag/offset, is different than the order in which you figure out which bits are which: offset/index/tag.)

So in part (a) The block size is 1 word, so you need 0 offset bits (because <span><span><span>20</span>=1</span><span><span>20</span>=1</span></span>). You have 16 blocks, so you need 4 index bits to give 16 different indices (because <span><span><span>24</span>=16</span><span><span>24</span>=16</span></span>). That leaves you with the remaining 28 bits for the tag. You seem to have gotten this mostly right (except for the rows for "180" and "43" where you seem to have missed a few bits, and the row for "181" where you interchanged some bits when converting to binary, I think). You are correct that everything is a miss.

For part (b) The block size is 2 words, so you need 1 offset bit (because <span><span><span>21</span>=2</span><span><span>21</span>=2</span></span>). You have 8 blocks, so you need 3 index bits to give 8 different row indices (because <span><span><span>23</span>=8</span><span><span>23</span>=8</span></span>). That leaves you with the remaining 28 bits for the tag. Again you got it mostly right except for the rows for "180" and "43" and "181". (Which then will change some of the hits and misses.)

5 0
3 years ago
Read 2 more answers
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