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4vir4ik [10]
2 years ago
5

Suppose a small economy produces only two goods: books and shirts. The opportunity cost of 1 book is constant at 3 shirts. For e

xample, in order for this economy to produce 1 more book, 3 fewer shirts must be produced.
In the following table, fill in the number of shirts in each combination (given the number of books being produced).

Business
1 answer:
Anastaziya [24]2 years ago
8 0

Answer:

Books Shirts

4 0

3 3

2 6

1 9

0 12

Explanation: At combination E, the economy is producing 0 books and 12 shirts. Since the opportunity cost of 1 book is 3 shirts, moving from point E to point D (gaining 1 book) requires this economy to produce 3 fewer shirts. Thus, the number of shirts in combination D must be 12 shirts−3 shirts=9 shirts. The rest of the combinations can be calculated in a similar fashion, with the answers summarized in the following table.

A 4 3−3=0

B 3 6−3=3

C 2 9−3=6

D 1 12−3=9

E 0 12

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Answer:

In equilibrium, total output by the two firms will be option e= 300.  

Q = q_{1} + q_{2}

Q = 100 + 200

Q = 300

Explanation:

Data Given:

Market Demand Curve = P = 1660-4Q

where, P = price and Q = total industry output

Each firm's marginal cost = $60 per unit of output

So, we know that Q =  q_{1} + q_{2}

where q_{} being the individual firm output.

Solution:

P = 1660-4Q

P = 1660- 4(q_{1} + q_{2})

P = 1660 - 4q_{1} - 4q_{2}

Including the marginal cost of firm 1 and multiplying the whole equation by q_{1}

Let's suppose new equation is X

X =  1660q_{1} - 4q_{1} ^{2} - 4q_{1}q_{2} - 60q_{1}

Taking the derivative w.r.t to q_{1}, we will get:

X^{'} = 1660 - 8q_{1} - 4q_{2} - 60 = 0

Making rearrangements into the equation:

8q_{1} + q_{2} = 1660 - 60

8q_{1} + q_{2} = 1600

Dividing the whole equation by 4

2q_{1} +q_{2} = 400

Solving for q_{1}

2q_{1} = 400 - q_{2}

q_{1} = 200 - 0.5 q_{2}  

Including the marginal cost of firm 1 and multiplying the whole equation by q_{2}

P = 1660 - 4q_{1} - 4q_{2}

Let's suppose new equation is Y

Y =  1660q_{2} - 4q_{1}q_{2} -4q_{2} ^{2} - 60q_{2}

Pugging in the value of q_{1}

Y =  1660q_{2} - 4q_{2}(200 - 0.5 q_{2}) -4q_{2} ^{2} - 60q_{2}

Y =  1660q_{2} - 800q_{2} +2q_{2} ^{2} -4q_{2} ^{2} - 60q_{2}

Y =  1600q_{2} - 800q_{2} -2q_{2} ^{2}

Taking the derivative w.r.t q_{2}

Y^{'} = 1600 - 800 - 4q_{2} = 0

Solving for q_{2}

4q_{2} = 800

q_{2} = 200

q_{1} = 200 - 0.5 q_{2}

Plugging in the value of q_{2} to get the value of q_{1}

q_{1} = 200 - 0.5 (200)

q_{1} = 200 - 100

q_{1} = 100

Q = q_{1} + q_{2}

Q = 100 + 200

Q = 300

Hence, in equilibrium, total output by the two firms will be option

e= 300.

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Answer:

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Explanation:

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