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KIM [24]
2 years ago
13

made a profit of $21.00 selling lemonade. She sold her lemonade for $0.75 per cup, received a tip of $3 from a neighbor, but als

o had to buy each plastic cup she used for $0.10 per cup. Write an equation to represent this situation
Mathematics
1 answer:
olasank [31]2 years ago
3 0

Answer:

Step-by-step explanation:

0.75x+3-10x=21

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A store owner sells two pairs of running
makvit [3.9K]

<u>Answer:</u>

He will order 72 pairs of high tops

<u>Explanation:</u>

Given the store owner sells two pairs of running shoes for each pair of high tops

For every pair of high tops, he sells 2 pairs of running shoes

1 high top = 2 running shoes

He has planned to order 144 pairs of shoes

Therefore, 144 pair of running shoes = 144/2 = 72 pairs of high tops

Therefore, he will order 72 pairs of high tops

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2 years ago
31.8 miles/hr= ? Feet/sec
PSYCHO15rus [73]
1 mi = 5280 ft
1 h = 3600 s

therefore:

31.8\ \dfrac{mi}{h}=31.8\cdot\dfrac{5280}{3600}\ \dfrac{ft}{s}=46.64\ \dfrac{ft}{s}

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3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e.  \mu=61 and \sigma=9

To find :  The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and 34+3(9).

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between \mu and \mu+3(\sigma). (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between \mu and \mu+3(\sigma) = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

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