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4 years ago

Can someone make this is right? Thanks!!

Mathematics

2 answers:

Ray Of Light [21]4 years ago

8 0

Answer:

You are correct

Step-by-step explanation:

If you put the coordinates into a graph, you come out with a square that is slightly rotated.

omeli [17]4 years ago

3 0

<h3>You are correct. Nice work.</h3>

You should find that each side is 5 units long, so you have a rhombus. Also, each angle is 90 degrees so you have a rectangle. Combine the properties of a rhombus and a rectangle and you get a square as the best description.

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The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

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We will consider y = 3.

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Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

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