Question

Solve :- Ques 5 ) (a) .

Answer 1

Answer:

Hey There!

Let's solve...

We have

$\angle \: odb = \angle \: cao \\ \\ \angle \: dbo = \angle \: aco$

Using AA Criterion of Similarity we have

$\triangle \: obd \: - \triangle \: oac$

This implies that

$\frac{od}{ob} = \frac{oa}{oc} \to \frac{6}{3 + 2 } \: or \: \frac{6}{5} = \frac{oa}{oc} \\ \\ \to \: oa = \frac{6}{5} oc$

Now,

$ab = ao - bo \\ \\ = \frac{6}{5}oc - bo = \frac{6}{5}(od - oc) \\ - bo \\ \\ = \frac{6}{5}(6 + 4cm) - 5cm \\ \\ = 7cm$

Note:Every letters should be in capital, i don't have any option here so i can't do.

I hope it is helpful to you...

Cheers!_________