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3 years ago

Munnabhai knows the four values of agile manifesto by heart however he was confused when a customer.

1 answer:

5 0

The reason why Munnabhai could not recollect anything about short iterations in Agile Manifesto is that he missed to learn: Agile Principles.

<h3>What is software development life cycle (SDLC)?</h3>

Software development life cycle (SDLC) can be defined as a strategic process (methodology) that defines the key steps and stages that are used for the creation and implementation of high quality software programs (applications).

<h3>The types of models in SDLC:</h3>

Generally, there are six (6) types of models in software development life cycle (SDLC) and these are:

Big Bang Model

Waterfall Model

V-Shaped Model

Iterative Model

Spiral Model

Agile Model

According to Agile principles of the Agile Manifesto, there are four (4) core values that are used in Agile software development and these include:

Interactions and individuals over tools and processes.
Functioning software program over comprehensive documentation.
Collaboration with customers over contract negotiation.
Responding to a change rather than following a plan.

In conclusion, Munnabhai could not recollect anything about short iterations in Agile Manifesto because he missed to learn Agile principles.

<u>Complete Question:</u>

Munnabhai knows the four values of Agile Manifesto by heart. However, he was confused when a customer spoke with him highlighting Agile characteristics of short software development cycles on iterations, he could not recollect anything about short iterations in Agile Manifesto. What did he miss to learn about?

Group of answer choices.

A. Agile Principles.

B. Agile Guidelines.

C. Agile Methods.

D. Agile Phases.

Read more on Agile Manifesto here: brainly.com/question/25820251

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The average waist size for teenage males is 29 inches with a standard deviation of 1. 4 inch. If waist sizes are normally distri

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Using the normal distribution, it is found that 0.0764 = 7.64% of teenagers who will have waist sizes greater than 31 inches.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of $\mu = 29$ .

The standard deviation is of $\sigma = 1.4$ .

The proportion of teenagers who will have waist sizes greater than 31 inches is <u>1 subtracted by the p-value of Z when X = 31</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{31 - 29}{1.4}$

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1 - 0.9236 = 0.0764.

0.0764 = 7.64% of teenagers who will have waist sizes greater than 31 inches.

More can be learned about the normal distribution at brainly.com/question/24663213

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