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3 years ago

Allen and Ben both open new bank accounts with an initial

1 answer:

7 0

Use Continuous Compound Interest Formula:
A = Pe^rt
A = Future Amount
P = Initial Amount
r = Interest rate
t = Time

%2 = 2/100
= 0.02

A = 500.00e^(0.02)(4)
A = 541.6435338

Round to nearest cent:
A ≈ 541.64 -> Final Answer.

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What are the side lengths of the equilateral triangle?

Alchen [17]

$5x + (6x - 5) + (3x + 10) = 360$

$5x + 6x - 5 + 3x + 10 = 360$

$11x - 5 + 3x + 10 = 360$

$14x + 5 = 360$

$14x = 360 - 5$

$14x = 355$

$x = 25.36$

$x = 25.36$

$5x = 5 \times 25.36 = 126.8$

$6x - 5 = 6 \times 25.36 - 5 = 147.16$

$3x + 10 = 3 \times 25.36 + 10 = 86.08$

4 0

3 years ago

Giselle pays $210 in advance on her account at the athletic club. Each time she uses the club, $15 is deducted from the account.

weqwewe [10]

Answer:

A.b = 210 + 15x

B.b = 210 – 15x

C.b = 195 + 15x

D.b = 195 – 15x

Step-by-step explanation

B is correct. Your starting amount is 210$ And you're taking away 15$ each time she uses the club,x.

3 0

3 years ago

Help. Will give brainly if correct 50 points, No wrong answers.

ExtremeBDS [4]

B and C are the answers

6 0

3 years ago

Read 2 more answers

1. Find a if x³ + ax² - x -8 is divisible by x -1

Amanda [17]

Answer:

a = 8

Step-by-step explanation:

x-1 = 0

x = 1

let x³ + ax² -x -8 be p(x)

hence, p(1) = (1)³ + a(1)² -1 -8 = 0 (since, x-1 is a factor)

= 1 + a - 1-8

= a - 8 = 0

therefore, a = 8

6 0

2 years ago

Please give me some answers

Luda [366]

Answer:

4) 12 different calzones

5) 15 ways

6) 8 outfits

Step-by-step explanation:

When counting the total number of combinations like these situations, multiply the number of choices of each type together

For 4: 3 sizes, times 4 fillings, is 12 different calzones

For a small calzone, there are 4 diffferent fillings to choose from, making 4 calzones,

For a medium calzone, there are 4 differnt fillings, making 4 more for a total of 8,

For a large calzone, there are 4 different fillings, making 4 more for a total of 12

The same logic applies to the other problems

3 0

3 years ago