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damaskus [11]
3 years ago
8

6. Find the average of the middle 80% of the

Mathematics
1 answer:
erica [24]3 years ago
8 0
6. Find the average of the middle 80% of the
following series: 3,7, 39, 41, 57, 84, 91, 95, 110,
144
070.5
067.1
O52.5
057
O 65.5
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What is triangle and types of triangle​
denis-greek [22]

Answer:

Step-by-step explanation:

A triangle is a polygon with three edges and three vertices and there are right triangle , obtuse triangles ,  acute triangles , isosceles triangles, equilateral triangle, and scalene triangles

7 0
4 years ago
The apartments in Brian's apartment house are numbered consecutively on each floor. The sum of his number and his next-door neig
e-lub [12.9K]
If sum of numbers (a) +(b) is 1419 and
(a)  and (b) are <span>neighbors , whe have:
a + b = 1419 and b-a = 1;
<=> </span>a + b = 1419  and  <span>a = b-1 ; 
so we have  b-1 + b = 1419 <=> 2b = 1420 <=> b=710 and a = 709
Answer: 710 and 709

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8 0
3 years ago
Read 2 more answers
Which of the expressions are equivalent to the one below? Check all that apply.
sdas [7]

Step-by-step explanation:

We need to find an expression that is equivalent to 4×(8+3)

We know that,

4×(8+3) = 4(11) = 44

Option (1).

(4 • 8) + 3 = 32+3 = 35. It is incorrect

Option (2).

(8 + 3) • 4 = (11) 4 = 44. It is correct.

Option (3).

4 • (3 + 8) = 4(11) = 44. It is correct.

Option (4).

4 • 8 + 4 • 3 = 32+12 = 44. It is correct.

Hence, the correct options are (2), (3) and (4).

8 0
3 years ago
Bob's Bakery makes 12 cakes and 36 muffins each hour.
N76 [4]
The answer is B hope it helped
8 0
3 years ago
Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un
Snowcat [4.5K]

Answer:

2nd car is running faster than the first car by 2.01 units.

Step-by-step explanation:

Let's assume that

  • the velocity of first car,

v_1\ =\ 20i\ +\ 25j

  • and the velocity of second car

v_2\ =\ 30i

=> speed of first car,

u_1\ =\ \sqrt{(20)^2+(25)^2}

      =\ \sqrt{400+625}

       =\ \sqrt{1025}

       = 32.01 units

and speed of second car,

u_2\ =\ \sqrt{(30)^2+(0)^2}

        = 30 units

u_2\ -\ u_1\ =\ 32.01\ -30

               = 2.01 units

Hence, 2nd car is running faster than the first car by 2.01 units.

8 0
3 years ago
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