Someone please help meeeeeeeeeeeeeeee
2 answers:
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Answer:
Step-by-step explanation:
Given that a shuttle launch depends on three key devices that may fail independently of each other with probabilities 0.01, 0.02, and 0.02, respectively.
Required probability = the probability for the shuttle to be launched on time
= Probability that all three do not fail
Since each key device is independent of the other
we have
prob that all three do not fail =
I am unsure about the very last problem but I can help with the first two
1) (y+1)+4
If we combine the numbers 1 and 4, we get +5 and can isolate the numbers from the variable.
This would give us
2) (6*r)*7
remember that we do not have to explicitly state 6*r
Instead, we can write it as 6r
this helps us get rid of the parentheses
now we can write it as
I hope this helps!:)
1) (y+1)+4
If we combine the numbers 1 and 4, we get +5 and can isolate the numbers from the variable.
This would give us
2) (6*r)*7
remember that we do not have to explicitly state 6*r
Instead, we can write it as 6r
this helps us get rid of the parentheses
now we can write it as
I hope this helps!:)