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Elena L [17]
2 years ago
7

What is the scale factor and center of dilation for this problem

Mathematics
1 answer:
Lena [83]2 years ago
5 0
The scale factor is (2,3)
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Factor 4a^2b^4-25x^6y^4
jeka57 [31]
4a²b⁴ - 25x⁶y⁴

(2ab²)² - (5x³y²)²     

= (2ab² + 5x³y²)(<span>2ab² - 5x³y²)    By difference of two squares</span>
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Evalute the piecewise function for the given values of x​
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How could you solve this system using elimination? Check all that apply
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3 years ago
Manuel bought 2kg of jelly beans and 2kg of gummy worms for a total of $26. Danny bought 2kg of jelly beans and 3kg of gummy wor
charle [14.2K]

Answer:

Jelly beans: $6 for 1 kg

Gummy worms: $7 for 1 kg

Step-by-step explanation:

In this question, we need to find the cost of 1kg of jelly beans and gummy worms.

To do this, make equations for both scenarios and solve:

2j + 2g = 26

2j + 3g = 33

Turn the bottom equation negative, as we will first solve for gummy worms (g).

2j + 2g = 26

-2j - 3g = -33

Solve:

-g = -7

Divide both sides by -1.

g = 7

We now know that gummy worms cost $7 for 1 kg

To solve for jellybeans (j), plug in 7 to g in one of the equations and solve:

2j + 2(7) = 26

2j + 14 = 26

Subtract 14 from both sides.

2j = 12

Divide both sides by 2.

j = 6

Jellybeans cost $6 for 1 kg.

Check answer by plugging in values to one of the equations:

2(6) + 2(7) = 26

12 + 14 = 26

26 = 26

3 0
3 years ago
It takes Sam 3 hours to rake leaves, but if Laura helps, it takes 2 hours. How long would it take Laura to rake the leaves on he
Klio2033 [76]

Answer:

6 hours

Step-by-step explanation:

Given that:

Time taken by Sam = 3 hours

Sam's rate = 1/3

Time taken : Sam + Laura = 2 hours

Sam's rate + Laura's rate = 1/2

Let time taken by Laura = x

1/3 + 1/x = 1/2

1/x = 1/2 - 1/3

1/x = (3 - 2) / 6

1/x = 1 /6

x = 6

Hencw, it will take 6 hours for Laura alone to rake leaves

6 0
2 years ago
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