Question

Hey guys, I need your help! Calculate the percent of Lead in Lead IV oxide

Answer 1

The percent by mass of Lead in Lead (IV) oxide ($PbO_2$) is equal to 86.62%.

Scientific data:

• Molar mass of Lead = 207.2 g/mol.

• Molar mass of oxygen = 16 g/mol.

To calculate the percent by mass of Lead in Lead (IV) oxide ($PbO_2$):

First of all, we would calculate the molar mass of Lead (IV) oxide ($PbO_2$);

$PbO_2 = 207.2 + 16(2)$

Lead (IV) oxide ($PbO_2$) = 239.2 g/mol.

How to calculate percent by mass.

For the percent by mass of Lead, we would calculate it by using this formula:

$P = \frac{Mass}{Mass\;of\;compound} \times 100$

Substituting the parameters into the formula, we have;

$P = \frac{207.2}{239.2} \times 100\\ \\ P=0.8662 \times 100$

Percent mass of Lead = 86.62%

Read more on percent mass here: brainly.com/question/15182450