3 years ago

How many atoms are in .83 mol hydrogen

Chemistry

1 answer:

horrorfan [7]3 years ago

3 0

No of moles=0.83mol

$\\ \tt\longmapsto No\:of\:atoms=No\:of\:moles\times Avagadro's constant$

$\\ \tt\longmapsto No\:of\: atoms=0.83(6.022\times 10^{23})$

$\\ \tt\longmapsto No\:of\: atoms=4.99\times 10^{23}$

You might be interested in

8Li<br> 8 Be<br> 0e<br> What type of radioactive decay is this?

lapo4ka [179]

Answer:

emitted i think

Explanation:

To determine the type of radiation (alpha, beta or gamma), first determine the background count rate, then the source count rate with no absorber. Next, place a sheet of paper between the source and the monitor. If the counts are significantly reduced, the source emits alpha particles.

5 0

3 years ago

Read 2 more answers

What is the mass of 1.56 X 10^24 formula units of Na2SO4?

Paladinen [302]

Answer:

$m=368 g$

Explanation:

Hello,

In this case, in order to compute the required mass, we first must notice that 6.022x10²³ formula units of sodium sulfate contain 1 mole of such compound (Avogadro's relationship). Moreover, one mole of sodium sulfate contains 142.04 g, which is in fact, the molar mass. Thereby, the required mass is computed via the following mole-mass-particles relationship:

$m=1.56x10^{24}f.u*\frac{1mol}{6.022x10^{23}f.u}*\frac{142.04g}{1mol} \\\\m=368 g$