Answer:
where is the problem?
Step-by-step explanation:
Volume
of a rectangular box = length x width x height<span>
From the problem statement,
length = 60 - 2x
width = 10 - 2x
height = x</span>
<span>
where x is the height of the box or the side of the equal squares from each
corner and turning up the sides
V = (60-2x) (10-2x) (x)
V = (60 - 2x) (10x - 2x^2)
V = 600x - 120x^2 -20x^2 + 4x^3
V = 4x^3 - 100x^2 + 600x
To maximize the volume, we differentiate the expression of the volume and
equate it to zero.
V = </span>4x^3 - 100x^2 + 600x<span>
dV/dx = 12x^2 - 200x + 600
12x^2 - 200x + 600 = 0</span>
<span>x^2 - 50/3x + 50 = 0
Solving for x,
x1 = 12.74 ; Volume = -315.56 (cannot be negative)
x2 = 3.92 ;
Volume = 1056.31So, the answer would be that the maximum volume would be 1056.31 cm^3.</span><span>
</span>
Given function : 
We need to identify a " initial amount", b "growth factor", r " rate of growth".
We know, exponential growth formula
, where a is initial amount, b is growth factor. On comparing with given function let us find values of a and b.
⇔ .
We can see a= 1.05 and b = 1.46.
Now, b=1+r.
Therefore, 1+r =1.46.
Subtracting 1 from both sides, we get
1+r-1 =1.46-1
r = 0.46.
On converting 0.46 into percentage, we get
0.46 × 100 = 46.
Therefore, intial amount a = a= 1.05 , growth factor b = 1.46, and the rate of growth r= 46%.
Answer:
Using a calculator, we can check that e=2.718281828.
Step-by-step explanation:
Lets evaluate each one of our expression the check which one is closest to e:
(1+ \frac{1}{31} )^{31}=2.675686306
(1+ \frac{1}{32})^{32}=2.676990129
(1+ \frac{1}{34} )^{34}=2.679355428
(1+ \frac{1}{33} )^{33}=2.678207651
We can conclude that the value of (1 +1/34) to the power of 34 is the closest to the value of e.
