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jek_recluse [69]
2 years ago
14

Deacrease 250 by 15%

Mathematics
1 answer:
ryzh [129]2 years ago
3 0

Answer:

212.5

Step-by-step explanation:

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the student to teacher ratio is 15:3. if there are 90 teachers at the school, how many students are there
mixas84 [53]
15x+3x=90\\
18x=90\\
x=5\\\\
15x=15\cdot5=\boxed{75}
8 0
3 years ago
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(4x1,000)+(5x100)+(9x10)+(2x1)+(7x1/10) in standard form
Igoryamba

Answer:

4592.7

Step-by-step explanation:

Add them up:

4000 + 500 + 90 + 2 + 0.7 = 4592.7

6 0
3 years ago
Value of m varies directly as value of n and n=5 when m=12. What is n when m=18?
ohaa [14]
Simplify the problem down, so:

m = 12 & n = 5
m = 6 & n = 2.5 <span>(divided each number by 20)
</span>
Now m is a factor of 18. Multiply each number by 3.
Answer: m = 18 & <span>n = 7.5</span>
6 0
3 years ago
Where do I put the other two
Ilya [14]
You can put h on -1 and sum on 0.4. Also, you put 1.4 in the wrong place. It should be three more places to the right.
4 0
3 years ago
Can Someone Answer My Final Answers :) I’d appreciate it so much :)
DaniilM [7]
1. Remember that the perimeter is the sum of the lengths of the sides of a figure.To solve this, we are going to use the distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
(x_{1},y_{1}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point
Length of  WZ:
We know form our graph that the coordinates of our first point, W, are (1,0) and the coordinates of the second point, Z, are (4,2). Using the distance formula:
d_{WZ}= \sqrt{(4-1)^2+(2-0)^2}
d_{WZ}= \sqrt{(3)^2+(2)^2}
d_{WZ}= \sqrt{9+4}
d_{WZ}= \sqrt{13}

We know that all the sides of a rhombus have the same length, so 
d_{YZ}=  \sqrt{13}
d_{XY}= \sqrt{13}
d_{XW}= \sqrt{13}

Now, we just need to add the four sides to get the perimeter of our rhombus:
perimeter= \sqrt{13} + \sqrt{13} + \sqrt{13} + \sqrt{13}
perimeter=4 \sqrt{13}
We can conclude that the perimeter of our rhombus is 4 \sqrt{13} square units. 

2. To solve this, we are going to use the arc length formula: s=r \alpha
where
s is the length of the arc. 
r is the radius of the circle.
\alpha is the central angle in radians

We know form our problem that the length of arc PQ is \frac{8}{3}  \pi inches, so s=\frac{8}{3} \pi, and we can infer from our picture that r=15. Lest replace the values in our formula to find the central angle POQ:
s=r \alpha
\frac{8}{3} \pi=15 \alpha
\alpha =  \frac{\frac{8}{3} \pi}{15}
\alpha = \frac{8}{45} \pi

Since \alpha =POQ, We can conclude that the measure of the central angle POQ is \frac{8}{45} \pi

3. A cross section is the shape you get when you make a cut thought a 3 dimensional figure. A rectangular cross section is a cross section in the shape of a rectangle. To get a rectangular cross section of a particular 3 dimensional figure, you need to cut  in an specific way. For example, a rectangular pyramid cut by a plane parallel to its base, will always give us a rectangular cross section. 
We can conclude that the draw of our cross section is:

6 0
3 years ago
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