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jek_recluse [69]
3 years ago
14

Deacrease 250 by 15%

Mathematics
1 answer:
ryzh [129]3 years ago
3 0

Answer:

212.5

Step-by-step explanation:

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6.04)The equation of the line of best fit of a scatter plot is y = −8x + 3. What is the the y-intercept? −8 −3 3 8
liberstina [14]
The y-intercept is 3...when plottibg this plot 3 first then use -8x (-8/1) as your slope form your y-intercept going both directions.
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Write an equation for the description: Tanmayi wants to raise $175 for a school fundraiser. She has raised $120 so far. How much
stealth61 [152]
Let c= monies still needed so 175=120+x
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4 years ago
15 POINTS!!!! <br> 7 ÷ 0.1 = 7 ÷ 1/10<br><br> 7 is 1/10 of____.<br><br> Help Please
lara [203]
7 is 70 out of 1/10.

please give thanks if i am correct, i think this is the question you're asking.
7 0
3 years ago
Read 2 more answers
2x - 3y = -5<br> 5x - 22 = -4y<br><br> Solve In Multiplication Method
Nimfa-mama [501]

Answer:

(2, 3 )

Step-by-step explanation:

Given the 2 equations

2x - 3y = - 5 → (1)

5x + 4y = 22 → (2) [ rearranged equation ]

Multiplying (1) by 4 and (2) by 3 and adding will eliminate the term in y

8x - 12y = - 20 → (3)

15x + 12y = 66 → (4)

Add (3) and (4) term by term to eliminate y, that is

23x = 46 ( divide both sides by 23 )

x = 2

Substitute x = 2 in either of the 2 equations and evaluate for y

Substituting into (2)

5)2) + 4y = 22

10 + 4y = 22 ( subtract 10 from both sides )

4y = 12 ( divide both sides by 4 )

y = 3

Solution is (2, 3 )

4 0
4 years ago
Any1 can help me wif q12
xenn [34]
I) HCF - use the smallest powers of each common factors
HCF (A,B) = 2^2 × 3^4 × 5^2

LCM - use the highest powers of each factors
LCM (A,B) = 2^4 × 3^6 × 5^2 × 7^2 × 11^16

ii) Add powers together.
A×B = 2^6 × 3^10 × 5^4 × 7^2 × 11^16
sqrt(A × B)
Divide powers by 2.
sqrt(A × B) = 2^3 × 3^5 × 5^2 × 7 × 11^8

iii) C = 3^7 × 5^2 × 7
Ck = (3^7 × 5^2 × 7) × k
B/c Ck should be a product that is a perfect cube, the powers of the products should be divisible by 3.
(3^7 × 5^2 × 7) × k = 3^9 × 5^3 × 7^3

k = (3^9 × 5^3 × 7^3) / (3^7 × 5^2 × 7)
k = 3^(9-7) × 5^(3-2) × 7^(3-1)
k = 3^2 × 5 × 7^2
8 0
4 years ago
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