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sweet-ann [11.9K]
2 years ago
15

Which equation best matches the scenario below?

Mathematics
1 answer:
siniylev [52]2 years ago
4 0

Answer:

Definetly t = 4n

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B 1,5

Step-by-step explanation:

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PLS HELP ILL MARK BRAINLYEST
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Step-by-step explanation:

1 - a

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Find the measure of the indicated angle.
marusya05 [52]

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the answer is 96°

Step-by-step explanation:

it is an isosceles triangle as it's 2 sides are equal.

for an isosceles triangle, the angles made by the equal sides with the third side are equal.

and the sum of all angles in a triangle = 180°

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What is the value of x in the equation –x = 4 – 3x + 6?
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Remember you can do anything to an equaiton as long as you do it to both sides


-x=4-3x
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Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.
Leviafan [203]

Answer:

Option D. 3.73​

Step-by-step explanation:

we know that

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

and

sin^{2}(\alpha)+cos^{2}(\alpha)=1

step 1

Find cos(X)

we have

sin(x)=\frac{1}{2}

we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

(\frac{1}{2})^{2}+cos^{2}(x)=1

cos^{2}(x)=1-\frac{1}{4}

cos^{2}(x)=\frac{3}{4}

cos(x)=\frac{\sqrt{3}}{2}

step 2

Find tan(x)

tan(x)=sin(x)/cos(x)

substitute

tan(x)=1/\sqrt{3}

step 3

Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(y)=1-\frac{2}{4}

sin^{2}(y)=\frac{2}{4}

sin(y)=\frac{\sqrt{2}}{2}

step 4

Find tan(y)

tan(y)=sin(y)/cos(y)

substitute

tan(y)=1

step 5      

Find tan(x+y)

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

7 0
3 years ago
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