2 years ago

Which equation best matches the scenario below?

Mathematics

1 answer:

siniylev [52]2 years ago

4 0

Answer:

Definetly t = 4n

You might be interested in

Point A is at (4,7). Find its new coordinate after it is translated 3 units left and 2 units down

VMariaS [17]

Answer:

B 1,5

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

PLS HELP ILL MARK BRAINLYEST

Vitek1552 [10]

Answer:

Step-by-step explanation:

1 - a

2 - c

3 - b

5 0

2 years ago

Find the measure of the indicated angle.

marusya05 [52]

Answer:

the answer is 96°

Step-by-step explanation:

it is an isosceles triangle as it's 2 sides are equal.

for an isosceles triangle, the angles made by the equal sides with the third side are equal.

and the sum of all angles in a triangle = 180°

42 + 42 + x = 180

x = 180 - 84

X = 96°

4 0

3 years ago

What is the value of x in the equation –x = 4 – 3x + 6?

Nataly [62]

Remember you can do anything to an equaiton as long as you do it to both sides

-x=4-3x
add 3x both sides
3x-x=4+3x-3x
2x=4+0
2x=4
divide 2
2x/2=4/2
2/2x=2
1x=2
x=2

7 0

3 years ago

Read 2 more answers

Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

3 years ago