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3 years ago

Given the function f(x) = 10x + 8, find each of the following. f(7)= f(-8)= f(0)=

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

6 0

Answer:

f(7)

Step-by-step explanation:

i am pretty sure i am not in highschool so just give me a thanks i am in 6 grade happy rest of the day

otez555 [7]3 years ago

4 0

Answer:8

Step-by-step explanation:

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What is the equation of the line that passes through the point (-2,14) and is perpendicular to the line with the following equat

tino4ka555 [31]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{5}}x-1\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-2}{5}} ~\hfill \stackrel{reciprocal}{\cfrac{5}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{5}{-2}\implies \cfrac{5}{2}}}$

so we're really looking for the equation of a line whose slope is 5/2 and it passes through (-2 , 14)

$(\stackrel{x_1}{-2}~,~\stackrel{y_1}{14})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{5}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{14}=\stackrel{m}{ \cfrac{5}{2}}(x-\stackrel{x_1}{(-2)}) \implies y -14= \cfrac{5}{2} (x +2) \\\\\\ y-14=\cfrac{5}{2}x+5\implies {\Large \begin{array}{llll} y=\cfrac{5}{2}x+19 \end{array}}$

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1 year ago

Can you help me with this problem thank you :)

Nikitich [7]

Well first you have to divide the 1 in = 8ft thing then after that multiply those together

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3 years ago

Find the slope of the line through each pair of points. (1/2, 2/3) and (3/2, 5/3)

solniwko [45]

$\bf (\stackrel{x_1}{\frac{1}{2}}~,~\stackrel{y_1}{\frac{2}{3}})\qquad (\stackrel{x_2}{\frac{3}{2}}~,~\stackrel{y_2}{\frac{5}{3}}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{~~\frac{5}{3}-\frac{2}{3}~~}{\frac{3}{2}-\frac{1}{2}}\implies \cfrac{~~\frac{3}{3}~~}{\frac{2}{2}}\implies \cfrac{1}{1}\implies 1$

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4 years ago

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