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wlad13 [49]
3 years ago
13

The diameter of a circle is 10 units what is the radius of the circle

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0

the Radius for a 10 unit diameter circle is 5

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A flat screen television measures diagonally 40 inches and 24 inches in length. What is the width of the television?
kvasek [131]

Answer:

The width of the television is 32 inches

Step-by-step explanation:

The given parameters are;

The diagonal length of the flat screen television = 40 inches

The length of the television screen = 24 inches

The width of the flat screen television is given by Pythagoras theorem as follows;

Diagonal² = Length² + Width²

Therefore;

Width² = Diagonal² - Length² =

Width² =  40² - 24² = 1024

∴ The width = √1024 = 32

The width = 32 inches

The width of the television = 32 inches.

4 0
4 years ago
3x/2 = 5<br><br><br> What's x????
Anni [7]
\frac{3x}{2} = 5
taking 2 to the other side ⇒ \frac{3x}{} = 5 x 2 
3x=10
taking 3 to the other side ⇒ x = \frac{10}{3}
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3 0
4 years ago
Read 2 more answers
On a coordinate plane, the segment with endpoints (10, 40) and (70, 120) is
OlgaM077 [116]

Answer:

The length of the resulting segment is 500.

Step-by-step explanation:

Vectorially speaking, the dilation is defined by following operation:

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)] (1)

Where:

O(x,y) - Center of dilation.

P(x,y) - Original point.

k - Scale factor.

P'(x,y) - Dilated point.

First, we proceed to determine the coordinates of the dilated segment:

(P(x,y) = (10, 40), Q(x,y) = (70, 120), O(x,y) = (0,0), k = 5)

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]

P(x,y) = (0,0) +5\cdot [(10,40)-(0,0)]

P'(x,y) = (50,200)

Q'(x,y) = O(x,y) + k\cdot [Q(x,y)-O(x,y)]

Q' (x,y) = (0,0) +5\cdot [(70,120)-(0,0)]

Q'(x,y) = (350, 600)

Then, the length of the resulting segment is determined by following Pythagorean identity:

l_{P'Q'} = \sqrt{(350-50)^{2}+(600-200)^{2}}

l_{P'Q'} = 500

The length of the resulting segment is 500.

3 0
3 years ago
A dog trainer has 104 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclos
vova2212 [387]

Answer:

  36 ft by 16 ft

Step-by-step explanation:

To solve this problem, you need to find dimensions of a rectangle such that the perimeter is 104 ft and the area is 576 ft. The perimeter is twice the sum of length and width, so the sum of length and width is 52 ft.

The area is the product of length and width, so if w represents the width, we have ...

  w(52 -w) = 576

  w² -52w = -576 . . . . . eliminate parentheses, multiply by -1

  w² -52w +26² = 26² -576 . . . . . .  complete the square

  (w -26)² = 676 -576 = 100

  w = 26 ±√100 =  {16, 36}

If the width is the short dimension, it is 16 feet. Then the length is 36 feet.

5 0
3 years ago
Find the area of shaded region where o is the centre of the circle<br>​
sukhopar [10]

Step-by-step explanation:

Hey mate..Area of shaded region= 115.5cm^2

8 0
3 years ago
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