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3 years ago

Is 62.90 bigger or 62.09?

2 answers:

5 0

62.90 is bigger than 62.09 because if you compare the 9s they are in different value place. The 9 in 62.90 is the first number behind decimal and is in the other number, 62.09, the number 9 is two places behind the decimal which makes it less. Also when you would round, the number 62.90 would still have a bigger value because of the place of the 9.

zhuklara [117]3 years ago

3 0

Answer:

62.90

Step-by-step explanation:

62 and 90 hundredths is more than 62 and 9 hundredths.

To compare decimal, try to say the decimal with its place value, and its way easier to compare.

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Find the lateral surface area of this

Jobisdone [24]

Answer:

22/7×9×3=22×9×3=594÷7=84.85

7 0

3 years ago

In Triangle XYZ, measure of angle X = 49° , XY = 18°, and

marissa [1.9K]

Answer:

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

$YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X$ (1)

If we know that $X = 49^{\circ}$ , $XY = 18$ and $YZ = 14$ , then we have the following second order polynomial:

$14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}$

$XZ^{2}-23.618\cdot XZ +128 = 0$ (2)

By the Quadratic Formula we have the following result:

$XZ \approx 15.193\,\lor\,XZ \approx 8.424$

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

$XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y$

$\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}$

$Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)$

1) $XZ \approx 15.193$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 54.987^{\circ}$

2) $XZ \approx 8.424$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 27.008^{\circ}$

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

6 0

3 years ago

There's four number of sides and two number of triangles what is the sum of the angle measures

jasenka [17]

The answer should be sixteen

3 0

4 years ago

Pleaseeee help!!!! I will mark you as brainlinest for correct answer!!!!

pshichka [43]

Yes, your answer is correct.

5 0

4 years ago

What is .825252525 repeating as a fraction

masya89 [10]

Let d = 0.825252525..., then
$10d = 8.25252525...=8\frac{25}{10^2-1}=8\frac{25}{99}$

Therefore,
$d=\frac{8}{10}+\frac{25}{990}=\frac{8(99)+25}{990}=\frac{817}{990}$

5 0

4 years ago