Well the LCM (lowest common multiples) for 8 and 32 would be 4. So plug 4 into "b" -8×4-32. -8×4=32. -32-32. Since you can't subtract 32 and 32 you add! Which gives you -64.
Hope this helps (:
Answer: the missing measure on the big rectangle is 30 feet.
Step-by-step explanation:
If the small rectangle was enlarged to create the big rectangle, it means that they are similar. This also means that the dimensions of the larger rectangle different form the dimensions of the smaller rectangle by a constant ratio or factor.
The smaller rectangle has a length of 12 feet and width of 2 feet. The larger rectangle has a length of x feet and width of 5 feet. This means that
x/12 = 5/2
Cross multiplying, it becomes
2x = 12 × 5 = 60
x = 60/2 = 30
Hello,
Using vectors and scalar product:
![[(a+c)*\vec{i}+(b-0)*\vec{j} ].[(a-c)*\vec{i}+(b-0)*\vec{j}]=0](https://tex.z-dn.net/?f=%5B%28a%2Bc%29%2A%5Cvec%7Bi%7D%2B%28b-0%29%2A%5Cvec%7Bj%7D%20%5D.%5B%28a-c%29%2A%5Cvec%7Bi%7D%2B%28b-0%29%2A%5Cvec%7Bj%7D%5D%3D0%20)
Thus
By the way how can we make text larger in latex \larger{.....} don't work.
Answer A
Answer: It will be C, 5x + 2y = 6 is equivalent to y = -5/2x + 3
