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andreyandreev [35.5K]
2 years ago
9

Is mass conserved when 40 g of sodium hydroxide undergoes a chemical change during an interaction with 36.5 g of hydrogen chlori

de? Use complete sentences to support your answer by explaining how this can be demonstrated.
Chemistry
1 answer:
vichka [17]2 years ago
6 0
Start by putting the dog in the basket then pick the grass out and play the tree
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Which describes the burning of fossil fuels?
Y_Kistochka [10]

Answer:

B. Greenhouse gases are released into the atmosphere.

I learn it in my bio class

7 0
3 years ago
Arrange the following elements in order of increasing from smallest to largest atomic size K,O, Cs, Se explain why the reason wh
lyudmila [28]

Answer:

smallest is O then Se then K then Cs.

Explanation:

These trends exist. elements tend to get smaller as it completes it's shell since there is more attraction when it is complete. plus the further down the periodic table you go the bigger it is. there are more electrons which repulse each other and make it bigger.

3 0
3 years ago
A 9.75 L 9.75 L container holds a mixture of two gases at 41 ° C. 41 °C. The partial pressures of gas A and gas B, respectively,
Triss [41]

Answer:

The total  pressure P = 1.642 atm

Explanation:

From the dalton's law

Total pressure of the mixture is

P = P_{A} + P_{B} + P_{C} ----- (1)

P_A = 0.419 atm

P_B = 0.589 atm

P_C = \frac{nRT}{V}

n = 0.24 mole

R = 0.0821 \frac{L.Atm}{K.mol}

T = 41 °c = 314 K

P_C = \frac{(0.24)(0.0821)(314)}{9.75}

P_C = 0.634 atm

From equation (1)

P = 0.419 + 0.589 + 0.634

P = 1.642 atm

Thus the total  pressure P = 1.642 atm

3 0
4 years ago
To cook in a dry heat is.<br> 1-Baking<br> 2-Broiling<br> 3-Boiling<br> 4-Sauteing
Degger [83]

Answer:

Baking

Explanation:

4 0
3 years ago
Balanced Chemical Equation: 2H2(g)+O2(g)——&gt; 2H2O(g)
Tcecarenko [31]

You must use 134 g O₂ to produce 118 g H₂O.

\%\text{ yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100 \%

\text{Theoretical yield} = \text{Actual yield}\times \frac{100\%}{\%\text{ yield}} = \text{118 g }\times \frac{100 \%}{78.2 \%} = \text{150.9 g}

M_r:          32.00    18.02  

         2H₂ + O₂ ⟶ 2H₂O

Moles of H₂O = 150.9 g H₂O × (1 mol H₂O/18.02 g H₂O) = 8.374 mol H₂O

Moles of O₂ = 8.374 mol H₂O × (1 mol O₂/2 mol H₂O) = 4.187 mol O₂

Mass of O₂ = 4.1877 mol O₂ × (32.00 g O₂/1 mol O₂) = 134 g O₂

6 0
4 years ago
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