1 Aluminium is oxidised Al - 3e = Al⁺³
2 Chlorine is reduced Cl⁺⁷ + 8e = Cl⁻¹
3 Nitrogen is oxidised 2N⁻³ - 6e = N₂
Answer:
Following are the solution to this question:
Explanation:
Please find the complete question in the attachment.
Start of Laboratory
Dissolve 2-naphthol in the round bottom flask with ethanol.
Add pellets of sodium hydroxide and hot chips. Attach a condenser.
Heat for 20 minutes under reflux, until the put a burden dissolves.
After an additional hour, add 1-Bromobutane and reflux.
Pour the contents into a beaker with ice from a round bottom flask.
On a Bachner funnel, absorb the supernatant by vacuum filtration.
Utilizing cold water to rinse the material and dry that on the filter.
Ending of the Lab
The volume of the gas will be decreased. Answer lies on the understanding of kinetic energy of particles and how particles occupy certain amount of space.
<span>I forgot to add: the answer is 50.91 difference in temperature. </span><span><span>
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Answer:
MnO2 M n O 2 is an ionic substance without any oxo-anions, therefore its name has the -ide ending.