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2 years ago

You must include an explanation accompanied with your solution. Answers without

Mathematics

1 answer:

nekit [7.7K]2 years ago

4 0

Answer:

B) $7.50

Step-by-step explanation:

Interest (I) = Principal (P) x Interest Rate (r) x Time (t, in years)

I = 125(.03)(2)

I = 7.5

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1. A rectangle is 3/4 as wide as it is long. How

s344n2d4d5 [400]

Answer:

B. 6 inches

Step-by-step explanation:

To find how wide it is, multiply the length by 3/4

8(3/4)

= 6

The width of the rectangle in 6 inches.

So, the correct answer is B. 6 inches

5 0

2 years ago

2^3 times 2^3+= <br> what does this eqaul

VLD [36.1K]

Answer:

Step-by-step explanation:

2x3 x 2x3 = 36

Sorry if this didnt help

3 0

2 years ago

Read 2 more answers

Find a fraction equivalent to<br> that has a denominator of 10.

quester [9]

Answer:

1/10

Step-by-step explanation:

any number (1-9) as the number above the fraction line (numerator) with the number 10 below the fraction line is a fraction with a denominator of 10.

if it was 10/10, it will = 1

5 0

3 years ago

If <img src="https://tex.z-dn.net/?f=tan%20%28x%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title="tan (x) = \frac{5}{12

Alekssandra [29.7K]

Explanation:

First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

$\sin x = -\frac{5}{13}\;\;\text{and}\;\;\cos x = -\frac{12}{13}$

Note that both sine and cosine are negative because x is in the 3rd quadrant.

Recall the addition identities listed below:

$\sin(\alpha + \beta) = \sin\alpha\sin\beta + \cos\alpha\cos\beta$

$\Rightarrow \sin(180+x) = \sin180\sin x + \cos180\cos x$

$\;\;\;\;\;\;= -\sin x = \dfrac{5}{13}$

$\cos(\alpha - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta$

$\Rightarrow \cos(180 - x) = \cos180\cos x + \sin180\sin x$

$\;\;\;\;\;\;=-\cos x = \dfrac{12}{13}$

$\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta}$

$\Rightarrow \tan(360 - x) = \dfrac{\tan 360 - \tan x}{1 + \tan 360 \tan x}$

$\;\;\;\;\;\;= -\tan x = -\dfrac{5}{12}$

Therefore, the expression reduces to

$\sin(180+x) + \tan(360-x) + \frac{1}{\cos(180-x)}$

$\;\;\;\;\;= \left(\dfrac{5}{13}\right) + \left(\dfrac{5}{12}\right) + \dfrac{1}{\left(\frac{12}{13}\right)}$

$\;\;\;\;\;= \dfrac{49}{26}$

5 0

2 years ago

Can someone give me a hand here?

IrinaVladis [17]

Answer:

49a^8, I hope this helps :)

4 0

2 years ago