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3 years ago

Can I get some up please?

Mathematics

1 answer:

qwelly [4]3 years ago

5 0

The answer is a it cant be anything else

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What is the opposite of taking a power of a number called

frutty [35]

Square rooting a number

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3 years ago

An office and apartment building is made up of modules. Each module is a rectangular prism. The building has 150 modules, and is

Elis [28]

Answer:

Part 1) 10 modules per floor

Part 2) Two different rectangular prism

Step-by-step explanation:

Part 1)

Let

x ----> the number of modules

y ---> the number of stories

we have

$x=150\ modules\\y=15\ stories$

Divide the number of modules by the number of stories

$\frac{x}{y}=\frac{150}{15}=10\ \frac{modules}{floor}$

Part 2) How many different rectangular prisms could be made from that number?

The number is 10

Look at the factors of 10

They are 1,2 ,4,5 and 10

Pick any two of these factors and determine if there is a third value from this list so that the product of the three factors is 10

There are 2 combinations that will work :

1 0×1×1

2 ×5×1

4 0

3 years ago

Enter a negative number that is greater than -8

Art [367]

Answer:

-7

Step-by-step explanation:

5 0

3 years ago

Mark is playing soccer. He is

eimsori [14]

Answer:

it would be 3 yards because it went 2° to the right

7 0

3 years ago

Pls help with 29..tank you

trapecia [35]

Answer:

See below

Step-by-step explanation:

Let the 2 roots be A and A^2.

Then A^3 = c/a and A + A^2 = -b/a.

Using the identity a^3 b^3 = (a + b)^3 - 3ab^2 - 3a^2b:-

A^3 + (A^2)^3 = ( A + A^2)^3 - 3 A.A^4 - 3 A^2. A^2

= (A + A^2)^3 - 3A*3( A + A^2)

Substituting:-

c/a + c^2/a^2 = (-b/a)^3 - 3 (c/a)(-b/a)

Multiply through by a^3:-

a^2c + ac^2 = -b^3 + 3abc

Factoring:-

ac(a + c) = 3abc - b^3

This is not the formula required in the question but let's see if the formula in the question reduces to this. If it does we have completed the proof.

a(c - b)^3 = a(c^3 - 3c^2b + 3cb^2 - b^3) = ac^3 - 3ac^2b + 3acb^2 - ab^3

c(a - b)^3 = c(a^3 - 3a^2b + 3ab^2 - b^3) = ca^3 - 3a^2bc + 3acb^2 - cb^3.

These are equal so we have

ca^3 - 3a^2bc + 3acb^2 - cb^3 = ac^3 - 3abc^2 + 3acb^2 - ab^3

The 3acb^2 cancel out so we have:-

a^3c - ac^3 = 3a^2bc - 3abc^2 + b^3c - ab^3

ac(a^2 - c^2) = 3abc( a - c) + b^3(c - a)

ac(a + c)(a -c) = 3abc(a - c) - b^3 (a - c)

Divide through by (a - c):-

ac(a + c) = 3abc - b^3 , which is the result we got earlier.

This completes the proof.

3 0

3 years ago

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