a= 6-2b-3c
then put that equation inside the first one and then the second one
you get -6*(6-2b-3c)+2b-3c=23
and 5*(6-2b-3c)+4b-3c=-12
14b-15c=59
14b-18c=18/*(-1)
--------------------
3b=41
THat would be A , B, C and E
-1\4
Step-by-step explanation:
find the gradient of the line
The answer is 4.5 l
To calculate this, we will use the Boyle's law using constant k, pressure P, and volume V:
PV = k
We can forget temperature since it is constant.
We have:
P1V1 = k
P2V2 = k
So, P1V1 = P2V2
P1 = 3 atm
V1 = 1.5 l
P2 = 1 atm
V2 = ?
_____
P1V1 = P2V2
3 atm * 1.5 l = 1 atm * V2
4.5 atm/l = 1 atm * V2
V2 = 4.5 atm l / 1 atm
V2 = 4.5 l
