I need some help with this.

Describe how Newton’s third law applies to the box and the table.

Snowcat [4.5K]

Answer:

the box has vertical force on the table

Explanation:

There can be no single isolated force, for every action there must be a force of reaction of ingual magnitude and direction, but in the opposite direction

3 0

3 years ago

Read 2 more answers

Modeled after the two satellites problem (slide 12 in Lecture13, Universal gravity), imagine now if the period of the satellite

ikadub [295]

Answer:

R = 6.3456 10⁴ mile

Explanation:

For this exercise we will use Newton's second law where force is gravitational force

F = m a

The satellite is in a circular orbit therefore the acceleration is centripetal

a = v² / r

Where the distance is taken from the center of the Earth

G m M / r² = m v² / r

G M / r = v²

The speed module is constant, let's use the uniform motion relationships, with the length of the circle is

d = 2π r

v = d / t

The time for a full turn is called period (T)

Let's replace

G M / r = (2π r / T)²

r³ = G M T²²2 / 4π²

r = ∛ (G M T² / 4π²)

We have the magnitudes in several types of units

T = 88.59 h (3600 s / 1h) = 3.189 10⁵ s

Re = 6.37 10⁶ m

Let's calculate

r = ∛ (6.67 10⁻¹¹ 5.98 10²⁴ (3,189 10⁵)²/4π²)

r = ∛ (1.027487 10²⁴)

r = 1.0847 10⁸ m

This is the distance from the center of the Earth, the distance you want the surface is

R = r - Re

R = 108.47 10⁶ - 6.37 10⁶

R = 102.1 10⁶ m

Let's reduce to miles

R = 102.1 10⁶ m (1 mile / 1609 m)

R = 6.3456 10⁴ mile

6 0

3 years ago

A physical pendulum consists of a uniform solid disk (of radius R 2.35 cm) supported in a vertical plane by a pivot located a di

lutik1710 [3]

Answer:

T = 0.3658

Explanation:

The expression to use to calculate the period is the following:

T = 2π √I/Mgd (1)

Where:

I: moment of Innertia of pendulum

g: gravity acceleration (9.81 m/s²)

d: distance of the pivot

M: mass of the disk.

Before we do anything, we will find first the moment of Innertia of the pendulum.

This can be calculated with the following expression:

I = 1/2 MR² + Md² (2)

At the moment we don't have the mass of the disk, but we don't need it, we will express I in function of M, and then, it will be canceled with the M of expression (1). Calculating M we have (Remember that the units of radius and distance should be in meter):

I = 1/2 M(0.0235)² + M(0.0175)²

I = (2.76x10^-4)M + (3.06x10^-4)M

I = (5.82x10^-4)M (3)

Now, we will replace this value in equation (1):

T = 2π √(5.82x10^-4)M / (9.81)*(0.0175)M ---> Here M cancels out

T = 2π √(5.82x10^-4) / (9.81)*(0.0175)

T = 2π * 0.0582

T = 0.3658 s

This is the period of the pendulum

7 0

3 years ago

Which of Earths layers is made up of liquid metal

wolverine [178]

The outer core is made out of molten lava also known as liquid metal because of all the iron and other metals in it

7 0

3 years ago

A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar

finlep [7]

Answer:

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

$\displaystyle V=k\frac{Q}{r}$

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

$d=\sqrt2 a$

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

$\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}$

$\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m$

The total potential is

$V_t=V_1+V_2+V_3+V_4$

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of $\pm 3\mu\ C$ . Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

$\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}$

$V_1=V_2=50912\ V$

The total potential is

$V_t=50912\ V+50912\ V=1\times 10^5\ V$

$\boxed{V_t=1\times 10^5\ V}$

6 0

3 years ago