Answer:
The speed of the wind is 25 km/hr.
Explanation:
Let us call
the speed of the plane and
the speed of the wind. When the plane is flying against the wind, it covers the distance of 900-km in 2 hours (120 minutes); therefore;
(1). 
And when the plane is flying with the wind, it covers the same distance in 1 hour 48 minutes (108 minutes)
(2). 
From equation (1) we solve for
and get:
,
and by putting this into equation (2) we get:





or in km/hr this is


Explanation
If you graph the force on an object as a function of the position of that object, then the area under the curve will equal the work done on that object, so we need to find the area under the function to find the work
Step 1
find the area under the function.
so
Area:


so

therefore, the answer is

I hope this helps you
Answer:
The number of atoms are
.
Explanation:
Given that,
Diameter 

Distance = 2.60 cm
We calculate the number of atoms
Using formula of numbers of atoms


Hence, The number of atoms are
.
Answer:
you want to know newtons first law here.
Explanation:
An object that is at rest stays at rest or stays in motion.
Answer:
v = 3.08 km/s
Explanation:
Given that,
The angular velocity of the satellite = 
A satellite is in orbit 36000km above the surface of the earth.
The radius of the earth is 6400 km
Let v is the velocity of the satellite. It can be calculated as :

So, the velocity of the satellite is 3.08 km/s.