Question

It has been suggested that rotating cylinders about 12.5 mi long and 3.99 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth

Answer 1

Answer:

The correct answer to the following question will be "0.0562 rad/s".

Explanation:

$r =\frac{3.9}{2}\times 1609.34$

  $=3138.213\ m$

As we know,

⇒  $\omega^2 \ r=g$

On putting the values, we get

⇒  $\omega^2\times 3138.213=9.8$

⇒  $\omega = \sqrt{\frac{9.8}{3138.213}}$

⇒  $\omega = 0.0562 \ rad /s$