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3 years ago

What is the formula for calculating mechanical power

Physics

1 answer:

Oksi-84 [34.3K]3 years ago

6 0

Answer:

Because work can be defined as force time distance, we can also use the following equation

Solution

P=power (w or ft-lbf/s)

F=force (N or lbf)

D=distance (m or ft)

T=time (sec)

One horsepower is equivalent to 550 ft-lbf/s and 745.7 watts.

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Earth's tides are primarily caused by _____.

Fiesta28 [93]

B.) The moon

There you go.

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4 years ago

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A mercury barometer reads 745.0 mm on the roof of a building and 760.0 mm on the ground. Assuming a constant value of 1.29 kg/m3

Ipatiy [6.2K]

Answer:

The height of the building is 158.140 meters.

Explanation:

A barometer is system that helps measuring atmospheric pressure. Manometric pressure is the difference between total and atmospheric pressures. Manometric pressure difference is directly proportional to fluid density and height difference. That is:

$\Delta P \propto \rho \cdot \Delta h$

$\Delta P = k \cdot \rho \cdot \Delta h$

Where:

$\Delta P$ - Manometric pressure difference, measured in kilopascals.

$\rho$ - Fluid density, measured in kilograms per cubic meter.

$\Delta h$ - Height difference, measured in meters.

Now, an equivalent height difference with a different fluid can be found by eliminating manometric pressure and proportionality constant:

$\rho_{air} \cdot \Delta h_{air} = \rho_{Hg} \cdot \Delta h_{Hg}$

$\Delta h_{air} = \frac{\rho_{Hg}}{\rho_{air}} \cdot \Delta h_{Hg}$

Where:

$\Delta h_{air}$ - Height difference of the air column, measured in meters.

$\Delta h_{Hg}$ - Height difference of the mercury column, measured in meters.

$\rho_{air}$ - Density of air, measured in kilograms per cubic meter.

$\rho_{Hg}$ - Density of mercury, measured in kilograms per cubic meter.

If $\Delta h_{Hg} = 0.015\,m$ , $\rho_{air} = 1.29\,\frac{kg}{m^{3}}$ and $\rho_{Hg} = 13600\,\frac{kg}{m^{3}}$ , the height difference of the air column is:

$\Delta h_{air} = \frac{13600\,\frac{kg}{m^{3}} }{1.29\,\frac{kg}{m^{3}} }\times (0.015\,m)$

$\Delta h_{air} = 158.140\,m$

The height of the building is 158.140 meters.

5 0

3 years ago

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How much energy is released when a proton combines with a deuterium nucleus to produce 3He?

slava [35]

Answer:

E = 7.99 *10^{-13} J

Explanation:

the given reaction is

$_1 H^1 + _1 H^2 = _2 He^3$

we know that energy is given as $E = \Delta mc^2$ $E = (m_1 H^1 + m_1 H^2 - _2 He^3)c^2$

where

m_1 H^1 is mass of proton = 1.672622 *10^{-27}

m_1 H^2 is mass of deuterium = 3.344494 *10^{-27}

m_2 H^3 is mass of He = 5.008234 *10^{-27}

E = [1.672622 *10^{-27} + 3.344494 *10^{-27} - 5.008234 *10^{-27} ] *(3*10^8)^2

E = 7.99 *10^{-13} J

6 0

3 years ago

Describe the movement of heat energy by the process of convection

atroni [7]

Answer:

Transfer of molecules due to density-difference resulting from increased temperature of the layers of fluid bulk leads to convection.

Explanation:

When a mass of fluid is heated form the lower layers then due to the variation of the density of the fluid at different temperature we observe the movement of molecules leading to convection.

When the lowest level of the fluid is heated it gains temperature and the molecular bulk expands on heating and its density becomes low with respect to the bulk fluid around it and hence it flows upwards to the top most layer being lighter in weight and the lowest layer is occupied by the subsequent colder and denser layer.

Then again the lowest layer is heated and the process continues forming a cycle heating through the bulk transfer of fluid layers called convention.

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4 years ago

The drawing shows a tire of radius R on a moving car

masha68 [24]

Answer:

H / R = 2/3

Explanation:

Let's work this problem with the concepts of energy conservation. Let's start with point P, which we work as a particle.

Initial. Lowest point

Em₀ = K = 1/2 m v²

Final. In the sought height

$Em_{f}$ = U = mg h

Energy is conserved

Em₀ = $Em_{f}$

½ m v² = m g h

v² = 2 gh

Now let's work with the tire that is a cylinder with the axis of rotation in its center of mass

Initial. Lower

Em₀ = K = ½ I w²

Final. Heights sought

Emf = U = m g R

Em₀ = $Em_{f}$

½ I w² = m g R

The moment of inertial of a cylinder is

I = $I_{cm}$ + ½ m R²

I= ½ $I_{cm}$ + ½ m R²

Linear and rotational speed are related

v = w / R

w = v / R

We replace

½ $I_{cm}$ w² + ½ m R² w² = m g R

moment of inertia of the center of mass

$I_{cm}$ = ½ m R²

½ ½ m R² (v²/R²) + ½ m v² = m gR

m v² ( ¼ + ½ ) = m g R

v² = 4/3 g R

As they indicate that the linear velocity of the two points is equal, we equate the two equations

2 g H = 4/3 g R

H / R = 2/3

7 0

3 years ago

What is the formula for calculating mechanical power​

What is the formula for calculating mechanical power