I think is 4 but Iam not sure
Pka = - log ka
10.36 = - log ka
Ka = .......
Answer:
2 eV
Explanation:
The energy of a photon of light is given by the formula

where
h is the Planck constant
c is the speed of light
is the wavelength of the photon
In this problem we have:


is the wavelength of the photon
Therefore, the energy in Joules is

We want to convert this energy into electronvolts: we know that the conversion factor is

Therefore,

When base is added in order to increase the pH of a solution, it results in MOH salt <u>precipitating first.</u>
Equation :
MOH (s) ⇄ M⁺ (aq) ₊ OH⁻(aq)
K
= [M⁺] [OH⁻]
K
= 1.39×10⁻¹² and [M⁺] = 0.001M
∴ 1.39×10⁻¹² = (0.001M) [OH⁻]
[OH⁻] = 1.004×10⁻¹⁹M
pOH = -log [OH⁻] = 11.9
pH = 14 - pOH
= 14 - 11.9
<u>pH = 2.1</u>
To learn more about solubility equilibrium ;
https://brainly.in/question/9213521
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