<h3>
Answer: 1.6 mol (option 5)</h3>
Explanation:
<u>Mole Ratio of O₂ : NO</u>
Based on the balanced equation, the mole ratio of O₂ : NO is 5 : 4
∴ for every mole of O₂ reacted, ⁴/₅ moles of NO is produced
<u>Moles of NO</u>
since the number of mol of O₂ = 2.0 mol
then moles of NO produced = 2.0 mol × ⁴/₅
= 1.6 mol
∴ the moles of nitrogen monoxide that will form if we start with 2.0 moles of oxygen is 1.6 mol (option 5).
Answer:
Hey mate.....
Explanation:
This is ur answer....
<em>31,536,000 seconds
</em>
<em>drum roll, please… one year would equal 365 times 24 times 60 times 60 seconds…or 31,536,000 seconds! That's over 31 million seconds you have to spend over the next year....</em>
<em></em>
Hope it helps u,
Mark me brainliest pls....
FOLLOW ME! :)
Answer: 2.75%
Explanation:
![pH=-log [H+]](https://tex.z-dn.net/?f=pH%3D-log%20%5BH%2B%5D)
![3.26 = -log [H+]](https://tex.z-dn.net/?f=3.26%20%3D%20-log%20%5BH%2B%5D)
![[H+] = 5.495\times 10^{-4} M](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%205.495%5Ctimes%2010%5E%7B-4%7D%20M)
initial 0.020 0 0
eqm 0.020 -x x x
![K_a=\frac{[H+][A-]}{[HA]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%2B%5D%5BA-%5D%7D%7B%5BHA%5D%7D)
![K_a=\frac{[x][x]}{[0.020-x]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5Bx%5D%5Bx%5D%7D%7B%5B0.020-x%5D%7D)
![K_a=\frac{[5.495\times 10^{-4}]^2}{[0.020-5.495\times 10^{-4}]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5B5.495%5Ctimes%2010%5E%7B-4%7D%5D%5E2%7D%7B%5B0.020-5.495%5Ctimes%2010%5E%7B-4%7D%5D%7D)
percent dissociation = ![\frac{[H^+_eqm]}{[Acid_{initial}]}\times 100](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5E%2B_eqm%5D%7D%7B%5BAcid_%7Binitial%7D%5D%7D%5Ctimes%20100)
percent dissociation=
Thus percent dissociation= 2.75 %
I think it's D- Number of neutrons
Over the northern parts of the Pacific Ocean, the Maritime Polar air mass exists. This means that the air mass likely to be over the northern parts of the Pacific Ocean would be wet and cold.
