A solution is prepared by dissolving 50.0g C6H12O6 in 250g of water. What is the freezing point?

6. Geologists in Egypt and Ethiopia are comparing rock samples from rocks

Tcecarenko [31]

Answer:

Both are different.

Explanation:

Both rocks are different from one another because both formed from different types of rocks. Rock A was formed from small pieces of rock while on the other hand, Rock B was formed from liquid rock so they both have different sources of rocks from which they were formed. Forming at the same time does not show that they are similar to each other, it is their source which decides that they are similar or different.

4 0

2 years ago

Which of the following substances is most likely to be a liquid at room temperature?

nikitadnepr [17]

Answer:

The correct answer is d.hydrogen peroxide H₂O₂H₂O₂

Explanation:

Substances can be found in nature in different aggregation states. 

Agreggation states can be liquid, gas or solid.

The problem asks about which substance can be found in room temperature as liquid. Each subtances has different physical and chemical properties that determines in which state you can find them at room temperature.

Hydrogen peroxide is the only substance listed that is in liquid state at room temperature, all other substances are in gas state at room temperature.

3 0

3 years ago

NEED HELP ASAPPP What is the number of beryllium atoms in 78.0g of Be?

polet [3.4K]

Answer: number of atoms is 5.21 · 10^24

Explanation: Atomic mass of Be is 9.012 g/mol.

Number of moles n = m/M = 78.0 g / 9.012 g/mol =

Multiply this with Avogadro number Na = 6.022*10^23 1/mol

4 0

3 years ago

A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num

-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

$V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}$

$\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}$

B) Radius

$\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}$

$V = \frac{ 4}{3 }\pi r^{3}$

$r^{3} = \frac{3V }{4 \pi }\$

$r= \sqrt [3]{ \frac{3V }{4 \pi } }$

$r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}$

3 0

3 years ago

Theory that the lithosphere is divided into tectonic plates that slowly move on

vitfil [10]

Pute because I’m smart and I know the right answer

5 0

3 years ago