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1 year ago

5

I don’t know how to do this bro

1 answer:

Nana76 [90]1 year ago

7 0

Answer:

$2x^3-4x^2-x+\frac{14}{x+6}$

Step-by-step explanation:

Use synthetic division:

-6 | 2 8 -25 -6 14

<u>____-12_24_ 6_ 0</u>

2 -4 -1 0 | 14

-6 comes from x+6=0 where x=-6

We drop the first number 2 and multiply it by -6. We then combine 8 and -12 to get -4. We repeat this process until the last column. The answer will be in coefficients with a remainder if there is one.

Therefore, the correct answer is $2x^3-4x^2-x+\frac{14}{x+6}$ .

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mixas84 [53]

Answer:

x = 8

Step-by-step explanation:

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3 years ago

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What is n x 2 squared= 14

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Answer:

n=3.5

Step-by-step explanation:

2²=4

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2 years ago

Jeremy makes $4.70 every time he mows a lawn but it costs him $6.80 to refill his lawn mower with gas. If Jeremy mows 5 lawns us

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2 years ago

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Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = ___

devlian [24]

Answer:

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030 $cm^2$

and specific resistance (ρ) = $1.8 \times 10^{-6}$ ohm-cm.

Use the formula R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, $R=\frac{1.8 \times 10^{-6} \times 270}{0.030}$ ohm

Simplify:

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Therefore, the resistance of copper wire is, $1.62\times 10^{-2}$ Ω

8 0

3 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

2 years ago