Question

Line ST and point V are shown on the graph. On a coordinate plane, line S T goes through (negative 5, 0) and (5, 2). Point V is at (0, negative 2). Line VW is to be drawn on the graph such that it is perpendicular to line ST. If the coordinates of point W are (â’1, y), what is the value of y? â’7 â’5 2 3.

Answer 1

The value of y in the coordinates of point W is 3

The points are given as:

$S = (-5,0)$

$T = (5,2)$

$V = (0,-2)$

$W = (-1,y)$

Start by calculating the slope of line ST

$m=\frac{y_2 - y_1}{x_2 -x_1}$

So, we have:

$m=\frac{2- 0}{5--5}$

$m=\frac{2}{10}$

$m=\frac{1}{5}$

Next, calculate the slope of line VW

$m=\frac{y_2 - y_1}{x_2 -x_1}$

So, we have:

$m = \frac{y --2}{-1-0}$

$m = \frac{y +2}{-1}$

$m = -y -2$

Since both lines are perpendicular, then the product of the slopes is -1.

So, we have:

$\frac 15 \times (-y -2) = -1$

Divide both sides by -5

$y +2 = 5$

Subtract 2 from both sides

$y = 3$

Hence, the value of y in the coordinates of point W is 3

Read more about line coordinates at:

brainly.com/question/2037439

Answer 2

3........or.............d