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Goryan [66]
2 years ago
6

If k-6=-3 the value of k is??_

Mathematics
2 answers:
vodomira [7]2 years ago
6 0

Answer:

k = 2

Step-by-step exeplayion

image a numner line, something minus 6 is -3. the number below in the number line and you go 6 down to get to -9, therefore k = 2

2

1

0

-1

-2

-3

photoshop1234 [79]2 years ago
4 0

Answer:

k=3

Step-by-step explanation:

k-6=-3

k-6+6=-3+6

k=3

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Step-by-step explanation:

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Please help me with this. Please!
jonny [76]

Answer:

214

Step-by-step explanation:

A circle is 360 degrees

Arc EF is 146 degrees

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4 0
3 years ago
Evaluate f(x)=x^2+1 for f(10)
marshall27 [118]
For f(10) replace x with 10 then solve:
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4 0
3 years ago
Find, corrrect to the nearest degree, the three angles of the triangle with the given vertices. A(1,0), B(3,6), C(-1,4)
Karo-lina-s [1.5K]

Answer:

45°, 45°, 90°

Step-by-step explanation:

Find the vectors to represent each sides

AB =<3-1, 6-0>=<2,6>  

AC = < -1-1, 4 - 0 > = < -2, 4>

Magnitude of the vectors

AB = √(2²+6²) = 6.32

AC = √ ((-2)² + 4²) = 4.47

cosθ = vector of AB × vector AC / ( Product of the magnitude of AB and AC) = 2 × (-2) + (6×4)/ (6.32×4.47) = 20 / 28.2504

θ = arcos(20 / 28.2504 ) approx = 45°

Magnitude of the vectors

BA =<1-3,0-6>=<-2,-6>

BC =<-1-3,4-6>=<-4,-2>

Magnitude of the vectors equals

BA = √((-2)² + (-6)²) = 6.325

BC = √((-4)² + (-2)²) = 4.4721

cosθ = (-2×-4) + (-6 ×-2) / (6.325 × 4.4721) = 20 / 28.286

θ  = arcos (20 / 28.286 ) = 45°

Magnitude of the vectors

CB =<3--1, 6-4>=<4,2>

CA=<1--1,0-4>=<2,-4>

Magnitude of the vector =

CB = √(4² + 2²) = 4.4721

CA = √(2² + (-4)²) = 4.4721

cosθ = (4×2) + (2×-4) / (4.4721×4.4721) = 0

θ = arcos 0 = 90°

4 0
3 years ago
33) AUVW ~ AQRS<br> 22<br> 159<br> U<br> W<br> 26<br> ?<br> 59<br> R<br> 13<br> S
Ad libitum [116K]

Answer:

.22+59+26+w=180

107+w=180

w=180-107=81

second triangle

59+13=72

180-72=108

5 0
3 years ago
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