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fgiga [73]
3 years ago
13

Directions: Complete each proof using the properties of equality. Not all rows be used.

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0

The answers for 13 and 14 are attached in the file.

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Describe a method you can use to find the area of the following shape. Provide specific details in your answer, including coordi
insens350 [35]
The area of figure ABCDEF can be computed as the sum of the areas of trapezoid ACDF and triangle ABC, less the area of trangle DEF.
  trapezoid ACDF area = (1/2)(AC +DF)·(CD) = (1/2)(8+5)(6) = 39
  triangle ABC area = (1/2)(AC)(2) = 8
  triangle DEF area = (1/2)(DF)(2) = 5

Area of ABCDEF = (ACDF area) + (ABC area) - (DEF area) = 39 +8 -5 = 42

The actual area of ABCDEF is 42 square units.

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3 years ago
Easy question - giving brainly if correct AND WORK IS SHOWN.​
k0ka [10]

Answer:

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Step-by-step explanation:

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3 years ago
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What is the adjacent
lesya [120]

Answer:

6 and 7

Step-by-step explanation:

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3 years ago
Please help me. I need to turn this 2y=3x+32 into standard form. PLEASE HELP
Artist 52 [7]

Answer:

3x - 2y = -32

Step-by-step explanation:

Ax + By = C

2y = 3x + 32

-3x  -3x

-3x + 2y = 32 (the leading coefficient needs to be positive)

-1(-3x + 2y = 32)

3x - 2y = -32

Hope this helps!

8 0
2 years ago
A certain social site has grown rapidly, Accerding to one repart, about 6 million users were added each day, How many users were
Licemer1 [7]

Answer:

69 users.

Step-by-step explanation:

First, we need to calculate the amount of seconds in one day.

a) Each hour has 60 minutes and each minute has 60 seconds.

Therefore, one hour has (60)(60) = 3600 seconds.

b) Since the day has 24 hours, we are going to multiply the total amount of seconds per hour by 24.

3600 (24) = 86400 seconds per day.

c) Now that we have the amount of seconds per day, we are going to divide the total amount of users added each day by the amount of seconds per day.

6000000/86400 = 69.44 users per second.

Therefore, 69 users are added, on average, each second.

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4 years ago
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