To express the height as a function of the volume and the radius, we are going to use the volume formula for a cylinder:
![V= \pi r^2h](https://tex.z-dn.net/?f=V%3D%20%5Cpi%20r%5E2h)
where
![V](https://tex.z-dn.net/?f=V)
is the volume
![r](https://tex.z-dn.net/?f=r)
is the radius
![h](https://tex.z-dn.net/?f=h)
is the height
We know for our problem that the cylindrical can is to contain 500cm^3 when full, so the volume of our cylinder is 500cm^3. In other words:
![V=500cm^3](https://tex.z-dn.net/?f=V%3D500cm%5E3)
. We also know that the radius is r cm and height is h cm, so
![r=rcm](https://tex.z-dn.net/?f=r%3Drcm)
and
![h=hcm](https://tex.z-dn.net/?f=h%3Dhcm)
. Lets replace the values in our formula:
![V= \pi r^2h](https://tex.z-dn.net/?f=V%3D%20%5Cpi%20r%5E2h)
![500cm^3= \pi (rcm^2)(hcm)](https://tex.z-dn.net/?f=500cm%5E3%3D%20%5Cpi%20%28rcm%5E2%29%28hcm%29)
![500cm^3=h \pi r^2cm^3](https://tex.z-dn.net/?f=500cm%5E3%3Dh%20%5Cpi%20r%5E2cm%5E3)
![h= \frac{500cm^3}{ \pi r^2cm^3}](https://tex.z-dn.net/?f=h%3D%20%5Cfrac%7B500cm%5E3%7D%7B%20%5Cpi%20r%5E2cm%5E3%7D%20)
![h= \frac{500}{ \pi r^2}](https://tex.z-dn.net/?f=h%3D%20%5Cfrac%7B500%7D%7B%20%5Cpi%20r%5E2%7D%20)
Next, we are going to use the formula for the area of a cylinder:
![A=2 \pi rh+2 \pi r^2](https://tex.z-dn.net/?f=A%3D2%20%5Cpi%20rh%2B2%20%5Cpi%20r%5E2)
where
![A](https://tex.z-dn.net/?f=A)
is the area
![r](https://tex.z-dn.net/?f=r)
is the radius
![h](https://tex.z-dn.net/?f=h)
is the height
We know from our previous calculation that
![h= \frac{500}{ \pi r^2}](https://tex.z-dn.net/?f=h%3D%20%5Cfrac%7B500%7D%7B%20%5Cpi%20r%5E2%7D%20)
, so lets replace that value in our area formula:
![A=2 \pi rh+2 \pi r^2](https://tex.z-dn.net/?f=A%3D2%20%5Cpi%20rh%2B2%20%5Cpi%20r%5E2)
![A=2 \pi r(\frac{500}{ \pi r^2})+2 \pi r^2](https://tex.z-dn.net/?f=A%3D2%20%5Cpi%20r%28%5Cfrac%7B500%7D%7B%20%5Cpi%20r%5E2%7D%29%2B2%20%5Cpi%20r%5E2)
![A= \frac{1000}{r} +2 \pi r^2](https://tex.z-dn.net/?f=A%3D%20%5Cfrac%7B1000%7D%7Br%7D%20%2B2%20%5Cpi%20r%5E2)
By the commutative property of addition, we can conclude that:
Answer:
1. 70
2. 65
3. 115
4. 65
5. 65
6. 65
7. 65
Step-by-step explanation:
All of them are correct so dont worry
Have a nice day
Most likely ill go with option c
Find the area of two sides (Length*Height)*2 sides.
Find the area of adjacent sides (Width*Height)*2 sides.
Find the area of ends (Length*Width)*2 ends.
Add the three areas together to find the surface area.
Example: The surface area of a rectangular prism 5 cm long, 3 cm. Hope this helps?!