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3 years ago

Solve the following equation 4=-3y-2

Mathematics

1 answer:

Mamont248 [21]3 years ago

8 0

Answer:

y = -2

Step-by-step explanation:

Move all the unknown no. to one side:

4 + 2 = -3y

-3y = 6

Solve the equation:

y = -2

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Let f(x) = 3x - 10. Find the value of f(-3).

laiz [17]

Easy, sub -3 for x
f(-3)=3(-3)-10
f(-3)=-9-10
f(-3)=-19

the value of f(-3) is -19

6 0

2 years ago

12(2x-10)+24 248 OR 6x +15-9x26 Graph the solution

Nezavi [6.7K]

Heudududuudidiirirururuririiririrjr

3 0

2 years ago

Remer 1) 5k? + 10k + 6 = 0

IceJOKER [234]

Ignoring the "?" in your question:

$5k+10k+6=0 \iff 15k+6=0 \iff k=-\dfrac{6}{15}$

If the "?" is a squared symbol that wasn't caught:

$5k^2+10k+6=0$

Use the quadratic formula

$x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

to get the solutions:

$x_{1,2}=\dfrac{-10\pm\sqrt{100-120}}{10}$

as you can see, the discriminant is negative, so the equation has no solution.

6 0

2 years ago

What is the distance between (4, -10) and (4,-4)?

bixtya [17]

Answer:

For x there is no distance since they are both for. For y, they are -6 apart.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the nth term?

kumpel [21]

Let $a_k$ denote the kth term of the sequence. Then

$a_k=a_1+d(k-1)$

where d is the common difference between consecutive terms in the sequence and a₁ is the first term.

The sum of the first n terms is

$S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n$

From the formula for $a_k$ , we get

$S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)$

$S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k$

$S_n=na_1+\dfrac{d(n-1)n}2$

$S_n=\dfrac n2(2a_1-d+dn)$

So we have $d=-5$ , and $2a_1-d=16$ so that $a_1=\frac{11}2$ .

Then the nth term in the sequence is

$a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}$

7 0

3 years ago