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monitta
3 years ago
14

The metalloid that is used to make computer chips is.

Engineering
2 answers:
Advocard [28]3 years ago
7 0

Answer:

the answer is semiconductors

Explanation:

semiconductors are used to make computer chips

NeX [460]3 years ago
3 0

Answer:

The metalloid used to make computer chips is Silicon!

Explanation:

Silicon has luster like a metal, but is brittle like a nonmetal. Silicon is used extensively in computer chips and other electronics because its electrical conductivity is in between that of a metal and a nonmetal.

Hope this helps!!

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May you tell me the meaning of "Tolerance is a bitter tree, but its fruit is sweet "by Aristotle
trapecia [35]

Answer:

“Patience is bitter, but its fruit is sweet. With patience you can bear up under any adversity and survive any defeat. With patience you can control your destiny and have what you will. Patience is the key to contentment, for you and for those who must live with you. To be brave without patience can kill you.

Explanation:

Aristotle’s Ethical Doctrine of the Mean. According to Aristotle’s ethical rule about the Golden Mean, to use a thing with virtue is a kind of moderation, as it leads the particular thing being in a good condition, and allows for its functions to be performed in a proper manner.

7 0
3 years ago
An insulated 40 ft^3 rigid tank contains air at 50 psia and 580°R. A valve connected to the tank is now opened, and air is allow
Pachacha [2.7K]

Answer:

The answer is "\bold{W_{in} = 645.434573 \ Btu}".

Explanation:

Its air enthalpy is obtained only at a given temperature by A-17E.  

The solution from the carbon cycle is acquired:

\to \Delta U= W_{in}-m_{out}h_{out}=0\\\\\to W_{in} = (m_1 - m_2)h

           =\frac{Vh}{RT}(P_1- P_2)\\\\= \frac{40 \times 138.66}{0.3704\times 580}(50-25) Btu\\\\= \frac{5,546.4}{214.832}(25) Btu\\\\= 25.8173829(25) Btu\\\\ =645.434573 Btu

W_{in} = 645.434573 \ Btu

8 0
3 years ago
You are the project manager assigned to construct a new 10-story office building. You are trying to estimate the costs for this
Semmy [17]

Answer:

Bottom-up Estimation

Explanation:

Bottom-up estimation is a type of project cost estimation that considers the cost of individual project activities and finally sums them up or finds the aggregates. The summation gives an idea of what the entire project will cost.

This is an effective way of estimating the cost of a project as it evaluates the costs on a wholistic basis. It also considers the tiniest details during the estimation process. The process moves from the simpler details to the more complicated details.

8 0
3 years ago
An isentropic steam turbine processes 2 kg/s of steam at 3 MPa, which is exhausted at50 kPa and 100C. Five percent of this flow
borishaifa [10]

Answer:

2285kw

Explanation:

since it is an isentropic process, we can conclude that it is a reversible adiabatic process. Hence the energy must be conserve i.e the total inflow of energy must be equal to the total outflow of energy.

Mathematically,

\\ E_{inflow} = E_{outflow}

Note: from the question we have only one source of inflow and two source of outflow (the exhaust at a pressure of 50kpa and the feedwater at a pressure of 5ookpa). Also the power produce is another source of outgoing energy    \\ E_{inflow} = m_{1} h_{1} .

\\

E_{outflow} = m_{2} h_{2} + m_{3} h_{3} + W_{out}

\\

Where m_{1} h_{1} are the mass flow rate and the enthalpies at the inlet  at a pressure of 3Mpa \\,

m_{2} h_{2} are the mass flow rate and the enthalpies  at the outlet 2 where we have a pressure of 500kpa respectively.\\,

and  m_{3} h_{3}   are the mass flow rate and the enthalpies  at the outlet 3 where we have a pressure of 50kpa respectively.\\,

We can now express write out the required equation by substituting the new expression for the energies \\

m_{1} h_{1} = m_{2} h_{2} + m_{3} h_{3} + W_{out}   \\

from the above equation, the unknown are the enthalpy values and  the mass flow rate. \\

first let us determine the enthalpy values at the inlet and the out let using the Superheated water table.  \\

It is more convenient to start from outlet 3 were we have a temperature 100^{0}C and pressure value of (50kpa or 0.05Mpa ). using double interpolation method  on the superheated water table to determine the enthalpy value with careful calculation we have  \\

h_{3}  = 2682.4 KJ/KG , at this point also from the table the entropy value ,s_{3} value is 7.6953 KJ/Kg.K. \\

Next we determine the enthalphy value at outlet 2. But in this case, we don't have a temperature value, hence we use the entrophy value since the entropy  is constant at all inlet and outlet. \\

So, from the superheated water table again, at a pressure of 500kpa (0.5Mpa) and entropy value of  7.6953 KJ/Kg.K with careful  interpolation we arrive at a enthalpy value of 3206.5KJ/Kg.\\

Finally for inlet one at a pressure of 3Mpa, interpolting with an entropy value of 7.6953KJ/Kg.K  we arrive at enthalpy value of 3851.2KJ/Kg. \\

Now we determine the mass flow rate at each inlet and outlet. since  mass must also be balance, i.e  m_{1} = m_{2} + m_{3} \\

From the question the, the mass flow rate at the inlet m_{1}}  is 2Kg/s \\

Since 5% flow is delivered into the feedwater heating,  \\

m_{2} = 0.05m_{1} = 0.05 *2kg/s = 0.1kg/s \\

Also for the outlet 3 the remaining 95% will flow out. Hence

m_{3} = 0.95m_{1} = 0.95 *2kg/s = 1.9kg/s \\

Now, from m_{1} h_{1} = m_{2} h_{2} + m_{3} h_{3} + W_{out}   \\ we substitute values

W_{out} = m_{1} h_{1}-m_{2} h_{2}-m_{3} h_{3}

W_{out} = (2kg/s)(3851.2KJ/Kg) - (0.1kg/s)(3206.5kJ/kg)- (1.9)(2682.4kJ/kg)

\\

W_{out} = 2285.19 kW.

Hence the power produced is 2285kW

7 0
3 years ago
List two important things to remember when using an ammeter.
Radda [10]

Answer:

Ammeters must always be connected in series with the circuit under test. Always start with the highest range of an ammeter. Deenergize and discharge the circuit completely before you connect or disconnect the ammeter. In dc ammeters, observe the proper circuit polarity to prevent the meter from being damaged.

Explanation:

3 0
3 years ago
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